If the line ax + 2Y + 2 = 0 is parallel to the line 3x-y-2 = 0, find the distance between the two parallel lines

If the line ax + 2Y + 2 = 0 is parallel to the line 3x-y-2 = 0, find the distance between the two parallel lines

First calculate the slope K1 = - A / 2, K2 = 3 is a = - 6
So the equation is - 3x + y + 1 = 0, 3x-y-2 = 0
The distance is three tenths, the root sign is ten

If the line x + (A-1) y + 1 = 0 is parallel to the line ax + 2Y + 2 = 0, then the value of a is______ ．

∵ the straight line x + (A-1) y + 1 = 0 and the straight line ax + 2Y + 2 = 0 are parallel to each other, ∵ A1 & nbsp; = 2A − 1 ≠ 21, that is, a = - 1, so the answer is - 1

If ax-2y-1 = 0 is parallel to 6x-4y + C = 0, then ()
A. A=3，C=-2B. A=3，C≠-2C. A≠3，C=-2D. A≠3，C≠-2

The slope of ∵ 6x-4y + C = 0 is 32, and the straight line ax-2y-1 = 0 is parallel to the straight line 6x-4y + C = 0 ∵ A2 = 32 & nbsp; C ≠ - 2. The solution is: a = 3, so choose: B