In solving the equation 2x-1 / 3 = x + A / 2-1, when the denominator is removed, both sides multiply by 6 at the same time, but THE-1 on the right side of the equation forgets to multiply by 6, so the solution obtained is x = 4. Try to find the value of a and correctly find the solution of the original equation

In solving the equation 2x-1 / 3 = x + A / 2-1, when the denominator is removed, both sides multiply by 6 at the same time, but THE-1 on the right side of the equation forgets to multiply by 6, so the solution obtained is x = 4. Try to find the value of a and correctly find the solution of the original equation

When solving the equation x = 1-5 X-1, the correct result after removing the denominator is

It's 5x = 15-3 (x-1)
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To solve the equation - x + 5 / 2x = 1 and 2 / 3x-3 = 5 / 1X without denominator

(1) 2x/(-x+5)=1 => 2x=-x+5 => 3x=5 => x=5/3;
(2) (3x-3)/2=5 => 3x-3=10 => 3x=13 => x=13/3;