It is known that the lengths of the two right angles of a right triangle are exactly the two roots of the square of the equation x-3x + 2 = 0. Find: (1) the sum of the lengths of the two right angles of the right triangle; (2) the area of the right triangle

It is known that the lengths of the two right angles of a right triangle are exactly the two roots of the square of the equation x-3x + 2 = 0. Find: (1) the sum of the lengths of the two right angles of the right triangle; (2) the area of the right triangle

The solution equation is: X & # 178; - 3x + 2 = 0
X = 2 or x = 1
Then: the two right angles of the triangle are: 1, 2
So the sum of the lengths of the two right sides of this right triangle: 1 + 2 = 3
The area of this right triangle: 1 × 2 △ 2 = 1

The sum of 5A plus a minus 18 multiplied by 2 equals 139

（5a+a-18）*2=139
12a-36=139
a=175/12

Three is the product of one minus two times four plus X

3=1-2（4+X）
3=1-8-2x
3=-7-2x
2x=-7-3
2x=-10
x= -5

18 times x plus 32 equals 98.6 to solve the equation

18x+32=98.6
18x=98.6-32
18x=66.6
x=3.7