【2/7X-32】+【2/5X+48】=X Solution x

【2/7X-32】+【2/5X+48】=X Solution x

Let 2y2-7x + 4 = (ay + BX + C) (Dy + ex + F) = ady2 + (AE + BD) XY + (AF + CD) y + (BF + CE) x + Bex2 + cf. you can find a 7-way system of coefficients. Ad = 2, AE + BD = 0, AF + CD = 0, BF + CE = - 1, be = 0, CF = 0 can be observed, because 2B or e at least 6 a c h is zero. If B = 0, then 7bd = 0 in the equation AE + BD = 0, AE = 0, because 7ad = 2, a is not equal to v0, Therefore, 1e = 0. B = e = 0 is contradictory to the o equation BF + CE = - 2, so 1 has no V factor and 0 solution, and no u solution is obtained
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3.5x () + 2.7x () + 2.8x () = 18.9 () = what

The test point of this problem is that the product of three numbers and the same number is 18.9, so we can find the same number
So you can do this:
（3.5+2.7+2.8)x()=18.9
9x()=18.9
()=2.1
So it should be 2.1 in brackets

8x=5x+24.9

8x=5x+24.9
8x-5x=24.9
3x=24.9
x=8.3