As shown in the figure, B and C divide the line segment ad into three parts, the ratio is ab: BC: CD = 2:3:4, M is the midpoint of the line segment ad, CM = 1cm, find the length of the line segment AD and the value of CM: CD Don't copy it!

As shown in the figure, B and C divide the line segment ad into three parts, the ratio is ab: BC: CD = 2:3:4, M is the midpoint of the line segment ad, CM = 1cm, find the length of the line segment AD and the value of CM: CD Don't copy it!

∵AB:BC:CD=2:3:4
∴AC=(2+3)AD/(2+3+4)=5AD/9
∵ m is the midpoint of AD
∴AM=AD/2
∴CM=AC-AM=AD/18=1cm
∴AD=18cm
CD=8cm
CM:CD=1:8

As shown in the right figure, if AB is 2cm long, CD is 6cm long, BC is 5cm long and De is 1cm long, then the total length of all line segments in the figure is () cm

Please see the picture above,

As shown in the figure, given that BC = 1 / 3AB = 1 / 4CD, points E and F are the midpoint of AB and CD respectively, and EF = 60cm, calculate the length of AB and CD
The picture is a -- E -- C -- B -- F -- D. I'm going to see you tonight

Because: BC = (1 / 3) AB = (1 / 4) CD, so: ab = 3bC, CD = 4bc; because: e, f are the midpoint of AB, CD respectively, so: AE = (1 / 2) AB = (3 / 2) BC, DF = (1 / 2) CD = 2BC; because: ad = AB + cd-bc = 6BC, so, EF = ad-ae-df = (5 / 2) BC; because:

As shown in the figure, given BC = 13ab = 14CD, points E and F are the midpoint of AB and CD respectively, and EF = 60cm, calculate the length of AB and CD

Let BC = xcm, from the meaning of the question: ab = 3x, CD = 4x ∵ e, f are ab respectively, the midpoint of CD ∵ be = 12ab = 32x, CF = 12CD = 2x ∵ EF = be + cf-bc = 32x + 2x-x, that is 32x + 2x-x = 60, the solution is x = 24 ∵ AB = 3x = 72 (CM), CD = 4x = 96 (CM). Answer: the length of line AB is 72 cm, and the length of line CD is 96 cm

It is known that: ab: BC: CD = 2:3:4, e and F are the midpoint of AB and CD respectively, and EF = 12 cm (CM). The length of ad is calculated (as shown in the figure)

Because AB: BC: CD = 2:3:4, e is the middle point of AB, f is the middle point of CD, if the line Ad9 is divided equally (9 = 2 + 3 + 4) and each part is set as a unit, then AB = 2, BC = 3, CD = 4, EB = 1, CF = 2. Thus EF = EB + BC + CF = 1 + 3 + 2 = 6, that is, EF accounts for 69 = 23 of the total length of AD

As shown in the figure, C is the point on the line AB, AC: BC = 2:3, e and F are the midpoint of AB and BC respectively, and EF = 3. Find the length of ab
You have to do it yourself,

AC: BC = 2:3, so AB has 2 + 3 = 5, EF = 1 + 1.5 = 2.5, which is half of AB, so AB = 3x2 = 6

As shown in the figure, points E and F are the midpoint of line segments AC and BC respectively. If EF = 3cm, then line segment ab=______ Cm

∵ points E and F are the middle points of line segments AC and BC respectively, ∵ CE = 12ab, BF = 12bc, ∵ EF = ce-cf = 12ac-12bc = 12 (ac-bc) = 3, ∵ ac-bc = 6, that is ab = 6

As shown in the figure, C is a point on the line AB, AC: BC = 2:3, e and F are the midpoint of AB and BC respectively, and EF = 3cm
|____ |____ |__ |______ |
A C E F B
I have the wrong number for the previous topic

Let AC = 2K, then BC = 3K
∴AB=5k
∵ e is the midpoint of ab
∴AE=BE=2.5k
∵ f is the midpoint of BC
∴CF=BF=1.5k
∴EF=BE-BF=2.5k-1.5k=k
∵EF=3
∴k=3
∴AB=5k=5*3=15cm

A_________ E___ B___ F___ C. As shown in the figure, points E.F are line segments AC.BC If EF = 5cm, how much is ab

AE=EC=1/2 AC,BF=FC=1/2 BC,
EF=EC-FC
=1/2AC-1/2BC
=1/2(AC-BC)
=1/2AB
=5
so,AB=2EF=10cm

As shown in the figure, e and F are the midpoint of line segments AC and ab respectively. If EF = 3, then BC=____
Is a line segment:
A ———— F —— E — B————— C
Hurry, hurry! I have to hand in my homework tomorrow. Is there anyone else here tonight, tut?

BC=AC-AB
=2AE-2AF
=2(AE-AF)
=2EF
=6