Using a simple algorithm to calculate the integral formula to compare the power of three integers Use a simple algorithm to solve the integral problem (1):8^2004*(-0.125)^2005 (2):0.25^2004*4^2005-8^100*0.5^300 (3):(-2.5)*(0.25)^5*0.4*(-4)^5 Compare the power of three integers: 3^555\4^444\5^333 (* is multiplied by)

Using a simple algorithm to calculate the integral formula to compare the power of three integers Use a simple algorithm to solve the integral problem (1):8^2004*(-0.125)^2005 (2):0.25^2004*4^2005-8^100*0.5^300 (3):(-2.5)*(0.25)^5*0.4*(-4)^5 Compare the power of three integers: 3^555\4^444\5^333 (* is multiplied by)


Use a simple algorithm to solve the integral problem
(1):8^2004*(-0.125)^2005
=-8^2004*(1/8)^2004*1/8
=-(8*1/8)^2004*1/8
=-1/8
(2):0.25^2004*4^2005-8^100*0.5^300
=(0.25*4)^2004*4-2^300*0.5^300
=4-(2*0.5)^300
=4-1
=3
(3):(-2.5)*(0.25)^5*0.4*(-4)^5
=-(-2.5*0.4)*(0.25)^5*4^5
=(0.25*4)^5
=1
Compare the power of three integers:
3^555\4^444\5^333
3^555=(3^5)^111=243^111
4^444=(4^4)^111=256^111
5^333=(5^3)^111=125^111
Because: 256 > 243 > 125
So, 4 ^ 444 > 3 ^ 555 > 5 ^ 333



1. Write 10 related application questions (must contain 2 unit one application questions) and answer them


1. The length of a rope is 4 / 5 meters. First use 1 / 4 and then use 1 / 4 meters. How many meters do you use? 4 / 5 × 1 / 4 + 1 / 4 ≈ 9 / 20
2. There are 50 goats, 3 more sheep than 4 / 5 goats. How many sheep are there? 50 × 4 / 5 + 3 ≈ 43
3. If you read a 120 page book, you have read one third of the whole book. How many more pages are exactly 5 / 6 of the whole book? 120 × 5 / 6 = 100 pages, 120 × 1 / 3 = 40, 100-40 = 60
4. A bottle of oil is 4 / 5 kg, and 3 / 10 kg has been used. How many kg more is exactly 1 / 2 of the barrel of oil? 4 / 5 × 1 / 2 = 2 / 5, 2 / 5-3 / 10 = 1 / 10
5. A bag of rice 120 kg, the first day to eat 1 / 4, the next day to eat the remaining 1 / 3, the next day to eat how many kg? 120 × 1 / 4 = 30, 120-30 = 90, 90 × 1 / 3 = 30
6. For a batch of goods, a car can transport 1 / 8 of it at a time, and how many parts of it can be transported four times? If this batch of goods weighs 116 tons, how many tons have been transported? 1 / 8 × 4 = 1 / 2 116 × 1 / 2 = 58
7. A factory uses 28 tons of water in October, which is 1 / 8 less than that in September. How many tons in September? 28 ± (1-1 / 8) = 32
8. A parallelogram is 24 meters long at the bottom and 3 / 4 of its height. How many square meters is its area? 24 × 3 / 4 = 18 × 24 = 432
9. Human blood accounts for 1 / 13 of body weight, and 2 / 3 of blood is water. Dad's weight is 78 kg. How many kg does his blood contain? 78 × 1 / 13 = 6 × 2 / 3 = 4
10. Among the sixth grade students, 160 trees were planted by girls, 5 less than 3 / 4 of boys. How many trees were planted by girls? 160 + 5 = 165 165 / 3 / 4 = 220
11. The number of students in grade 4 of Xinguang primary school is 4 / 5 of that in Grade 5, and that in grade 3 is 2 / 3 of that in grade 4. If there are 120 students in Grade 5, how many students are in grade 3? 120 × 4 / 5 = 96, 96 × 2 / 3 = 64



Do you want to write the unit of ratio of case to size in math application? I'm talking about the two numbers of ratio of case to size


If the original number has a unit, of course, the unit should be written
This is the first answer. I wish you progress!



Fill in the unit calculation
Fill in the unit: for example, 100 (m) + 0.9 (km) = 1 (km). What unit can make equations 10 () + 2 () = 1 () and 11 () + 13 () = 1 () hold?


10 (month) + 2 (month) = 1 (year)
11 (hours) + 13 (hours) = 1 (day)



There are two equal height containers (as shown in the figure). The bottom radius of the cone container is 3 decimeters, and the bottom radius of the cylinder container is 2 decimeters. First fill the cone container with water, and then pour all the water into the cylinder container. At this time, the water depth is 1 decimeter lower than 78 of the container height. The volume of the cylinder container is () cubic decimeters
A. 36πB. 32πC. 24πD. 18π


Let the height of the container be x decimeter, & nbsp; 13 × π × 3 × 3 × x = π × 2 × 2 × (78x-1), & nbsp; 3 π X - π × 72x + 4 × π = 0, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; 12 π x = 4 π, & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; The volume of the cylinder is: π × 2 × 8 = 32 π (cubic decimeter). A: the volume of the cylinder is 32 π cubic decimeter



When Xiaoming was measuring the mass of a solid, he mistakenly put the object to be measured on the right side of the tray balance. He added weights on the left side and moved the weights. When the balance was balanced, the sum of the weight mass and the weight indication was 35.4g, then the mass of the object to be measured was 35.4g______ g. (the smallest weight is 1g)


The minimum weight is 1g, and the sum of weight and traveling weight is 35.4g, then the mass of the weight in the disk is 35g, the traveling weight indication is 0.4g, and the mass of the object in the right disk is 35g-0.4g = 34.6g; so the answer is: 34.6



A 200 meter long train passes a 7000 meter long bridge at a constant speed. It takes six minutes for the train to pass the bridge completely. What's the speed of the train passing the bridge, km / h? (warm tips: don't forget to write the formula for the calculation problem!)


The distance of the train is s = 7000m + 200m = 7200m, the speed of the train is v = st = 7200m60s × 6 = 20m / S = 72km / h



The format of solving physics calculation problems


General steps of doing physics calculation problems:
1. Clear research object
2. Analyze each physical process of the research object
3. According to the theorems and laws, the formulas and equations of each process are listed (the more complex process may be the equations of the physical state before and after)
4. Solution (to have the ability of mathematical calculation oh)
Junior high school emphasizes: 1. Formula; 2. Substituting values and units; 3. Calculation results and units



What is the format of solving practical problems in physics?


Known (list the conditions provided by the title and sometimes simplify it)
Ask (to list the requirements of a topic)
Solution (start to solve, list formulas, replace data)
A (needless to say)



It is known that: x2-4x + 4 and | Y-1 | are opposite to each other, then the value of formula (XY − YX) / (x + y) is equal to ()
A. 0B. 1C. 0.5D. 13


∵ x2-4x + 4 = (X-2) 2, x2-4x + 4 and | Y-1 | are opposite numbers, X-2 = 0, Y-1 = 0, the solution is x = 2, y = 1, the original formula = (x + y) (x − y) XY × 1x + y = x − YXY, when x = 2, y = 1, the original 2 − 12 × 1 = 12 = 0.5