(Liangshan) it is known that the absolute values of xx-4x + 4 and (Y-1) are opposite to each other, then the value of formula (x / Y-Y / x) / (x + y) is equal to____

(Liangshan) it is known that the absolute values of xx-4x + 4 and (Y-1) are opposite to each other, then the value of formula (x / Y-Y / x) / (x + y) is equal to____

(xx-4x+4)+|y-1|=0
(x-2)^2 +|y-1|=0
x-2=0, y-1=0
x=2, y=1
(X/Y-Y/X)/(X+Y)
=(2 - 1/2)/3
=1/2

a. If B is opposite to each other and C and D are reciprocal to each other, then a + B-Cd + 1=_________

a. Then a + B-Cd + 1 = 0
Because AB is opposite to each other,
So a + B = 0
Because C and D are reciprocal,
So CD = 1
So 0-1 + 1 = 0

a. If B is opposite to each other and C.D is reciprocal to each other, then 1 / 5 (a + b) - 3 / CD

Because a and B are opposite numbers, a + B = 0
c. D is reciprocal to each other, so c * d = 1
So 1 / 5 (a + b) - 3 / CD = 1 / 5 * 0-3 / 1 = 0-3 = - 3

If a, B are opposite to each other and C, D are reciprocal to each other, then a + B =?

a. B is opposite to each other, C and D are reciprocal to each other
a+b=0,cd=1
A + B of CD
=0÷1
=0

If a and B are opposite to each other, and C and D are reciprocal to each other, then CD + A + B is 2 / 2=

If a and B are opposite to each other, C and D are reciprocal to each other
Then a + B = 0, c * d = 1
CD + A + B
=1/2+0
=1/2

If a and B are opposite to each other and C and D are reciprocal to each other, the absolute value of X is 1. Find the value of the algebraic formula x2 + (a + b) x-cd

a. B is opposite to each other, a + B = 0
c. D is reciprocal, CD = 1
The absolute value of X is 1, X & # 178; = 1
therefore
x2+(a+b)x-cd=1+0*x-1=0
Hope to help you

The absolute value of X is 2. Try to find X2 - (a + B + CD) x + (a + b) 2001 + (- CD)

X = plus or minus 2
, a + B = 0. CD = 1, bring in the formula = 4 + 2-1 = 5 or equal to 4-2-1 = 1

It is known that a B is opposite to each other and C D is reciprocal to each other. The square of X is equal to 4. Try to find the value of X2 - (a + B + CD) x + (a + b) 2011 + (CD) 2010

∵ a, B are opposite to each other, ∵ a + B = 0 ∵ C, D are reciprocal to each other, ∵ C · d = 1 ∵ X & # 178; = 4, ∵ x = ± 2. When x = 2, X2 - (a + B + CD) x + (a + b) 2011 + (CD) 2010 = 4-2 + 0 + 2010 = 2012. When x = - 2, X2 - (a + B + CD) x + (a + b) 2011 + (CD) 2010 = 4 + 2 + 0 + 2010 = 2016

It is known that a B is opposite to each other and C D is reciprocal to each other. The square of X is equal to 4. Try to find the value of X2 - (a + B + CD) x + (a + b) 2011 + (CD) 2014
It is known that a B is opposite to each other and C D is reciprocal to each other. The square of X is equal to 4. Try to find the value of X2 - (a + B + CD) + (a + b) 2013 + (- CD) 2014

A and B are opposite numbers, a + B = 0
C D reciprocal CD = 1
The square of X is 4, so x = ± 2
x^2-（a+b+cd）x+（a+b）^2011+（cd）^2014
= 4 - (0+1)^(±2) + 0^2011 + 1^2014
= 4 - 1 + 0 + 1
= 4

Given that a and B are opposite numbers, C and D are reciprocal numbers, the absolute value of X is 1, find the value of X - (a + B + 1 / CD)

a. B is opposite to each other,
Then a + B = 0
c. D is reciprocal to each other,
Then CD = 1
If the absolute value of X is 1, then x = ± 1
X - (a + B + 1 / CD of CD)
=1 - [(0 + 1) 1-1]
=1-（1-1）
=1