Q: rational numbers a, B, C, middle, b > a > C, and a and B are positive numbers, C is negative, simplification: 3 times a minus the absolute value of B minus 4 times a plus the absolute value of C plus B minus Q: rational numbers a, B, C, in which b > a > C, and a and B are positive numbers, C is negative. Simplification: 3 times a minus the absolute value of B minus 4 times a plus the absolute value of C plus the absolute value of B minus the absolute value of C

3 * | A-B | - 4 * | a + C | + | B-C |, if it is this formula
a> When = | C | we get: 4b-7a-5c
a

AB is a rational number, a is a negative number, B is a positive number, the absolute value of a is greater than the absolute value of B, then the absolute value of the sum of a plus B, plus the absolute value of the difference between a and B?

│A+B│+│A-B│=│A│-│B│+│A│+│B│=2│A│=-2A

If a + B < 0, ZB < 0, then a is greater than 0, b > 0, B is positive and negative, and the absolute value of positive number is greater than that of negative number
C a < 0 B < 0
The decimals of D AB are positive and negative, and the absolute value of negative number is greater than that of positive number

a+b＜0,ab＜0
The absolute value of negative number is greater than that of positive number

Given that a and B are rational numbers, and | a | = a, | B | = - B, then AB is ()
A. Negative B. positive C. negative or 0d. Nonnegative

∵|a | = a, ∵|a ≥ 0, ∵|b | = - B, ∵|b ≤ 0, ∵ ab ≤ 0, so C

a. The product of B and C is negative, the sum is positive, and x = absolute value of a / A + absolute value of B / B + absolute value of C / C + absolute value of AB / AB + absolute value of AC / AC + absolute value of BC / BC
Find the value of ax to the third power + BC to the second power + CX + 1

∵abc＜0 a+b+c＞0
There is only one negative number in ABC
When a < 0
Then b > 0, C > 0
x=-1+1+1-1-1+1
=0
The formula is 1
When B < 0
Then a > 0, C > 0
Similarly, x = 0
The original formula is 1
When C < 0
In the same way
The original formula is 1
in summary
The original formula is 1

Find the sum of the reciprocal of 2 and 1 / 3 and the opposite of the absolute value of - 3 / 7

(reciprocal of 2 and 1 / 3) + (- inverse of absolute value of 3 / 7)
=3/7+(-｜-3/7｜)
=3/7+(-3/7)
=0

The inverse of 2.6, the reciprocal, the absolute value ()

2.6 2.6 2.6

Given that a and B are reciprocal and m and N are opposite, find the value of 2010 (M + n) + 2Ab

A and B are reciprocal, ab = 1, m and N are opposite, M + n = 0
2010(m+n)+2ab=0+2=2

a. If B is opposite to each other and m and N are reciprocal to each other, then a + B / 2008-2010mn =?

It should be (a + b) / 2008-2010mn, otherwise there is no definite solution
∵ A and B are opposite to each other
A = - B, i.e. a + B = 0
∵ m and N are reciprocal
That is Mn = 1
∴(a＋b)/2008－2010mn＝0/2008－2010·1＝-2010

Given that a and B are opposite to each other, m and N are reciprocal to each other, | C | = 8, find the value of 3A + 3B + 2009mn + C

Because a and B are opposite numbers
So a + B = 0,
M and N are reciprocal
So Mn = 1
3a+3b+2009mn+c=3（a+b）+2009*1+c=2009+c
Because | C | = 8
So when C = 8, 3A + 3B + 2009mn + C = 2009 + C = 2009 + 8 = 2017
When C = 8 -, 3A + 3B + 2009mn + C = 2009 + C = 2009-8 = 2001