If a, B are opposite numbers and C, D are reciprocal numbers, then | 2010 (a + b) + (CD) 2009|= (CD) 2009 is the power of (CD)

If a, B are opposite numbers and C, D are reciprocal numbers, then | 2010 (a + b) + (CD) 2009|= (CD) 2009 is the power of (CD)

A and B are opposite numbers, so a + B = 0
C and D are reciprocal, so CD = 1
Original formula = 2010 * 0 + 1 ^ 2009 = 1

It is known that a and B are opposite to each other, and C and D are reciprocal to each other. When x = negative 2, find the value of the quadratic power of X - (a + B + CD) x + (a + b) and the square of X + (negative CD)

It is known that a and B are opposite to each other, C and D are reciprocal to each other,
a+b=0 cd=1
Then when x = - 2
Second power of X - (a + B + CD) 2009 of X + (a + b) + (negative CD) 2010
=4-（-2）+0+1
=7

The reciprocal of minus half

-2

If two and one-half and a are reciprocal, then a=

Two and one half = 5 / 2
If two and one-half and a are negative reciprocal of each other, the product is - 1
So a = - 2 / 5

The reciprocal of minus ten and a half

Minus ten and a half
＝-21/2
Reciprocal = - 2 / 21

What is the reciprocal of the inverse of the rich third and half

Two out of seven!
If my answer can give you some help, I hope not to be stingy to send a "praise"!

-(- two and a half) and () are opposite to each other, and (0) is reciprocal to each other

-(- two and a half) and (two and a half) are opposite to each other, and - two fifths are reciprocal to each other

-(- 2 half) and () are opposite to each other, and () are reciprocal to each other

-(- 1 / 2) and (- 1 / 2) are opposite to each other, and (2) are reciprocal to each other

If the quadratic trinomial AX2 + BX + C is a monomial with respect to X ()
A. a≠0，b=0，c=0B. a=0，b≠0，c=0C. a=0，b=0，c≠0D. a=0，b=0，c=0

One time monomial is the one with the number of times 1, so the conditions that meet the meaning of the question should be a = 0, B ≠ 0, C = 0

If the quadratic power + BX + C of the quadratic trinomial A is a monomial condition
Is ABC a constant

If ABC is constant, it will not be quadratic trinomial, because a & # 178; + C is constant and B is constant, then the original integral is quadratic integral. Therefore, the condition for monomial is: a = B (or x) = 0