For example, the converse of the following proposition is a false proposition 1. If one digit of an integer is 5, then the integer can be divided by 5 2. If both angles are right angles, then the two angles are equal

1. If one digit of an integer is 5, then the integer can be divided by 5
Inverse proposition: if an integer can be divided by 5, then the integer can be divided by 5
Example 10 20 30
2. If both angles are right angles, then the two angles are equal
Inverse proposition: if two angles are equal, then both are right angles
Example two acute angles of 30 degrees

True proposition: if the last digit of an integer is 0, then the integer can be divided by 5

If an integer can be divided by 5, then the number at the end of the integer is 0

If one digit of an integer is 2, then the integer can be divided by 2
What's wrong with this sentence? The topic says that it's a false proposition to give a counterexample

If one digit of an integer is 2, then the integer can be divided by 2
Inverse proposition: if an integer can be divided by 2, then the number of digits of the integer is 2
So the proposition is false

The absolute value of X

The absolute value of 1 + X / 4 - the absolute value of X - 2 / 8 = 1, x = what
What is the absolute value of 1 + X / 4 minus the absolute value of X - 2 / 8 = 1

2|1+X|-|X|=6
When x is greater than 0, x = 4
When x is less than 0, 2 (- x-1) + x = 6, x = - 8

-100 (x-1) squared = (- 4) cubic, then what is the value of X?

First of all, the cube of - 4 is equal to - 64, that is, the square of - 100 (x-1) = both sides of - 64 divided by - 100
It becomes the square of (x-1) = 0.64 (the - 100 on the left is eliminated) and then square left and right. The square of 0.64 equals 0.8 or - 0.8
That is, (x-1) = 0.8 or (x-1) = - 0.8, so x = 1.8 or 0.2

Given the third power of X + the second power of X + X + 1 = 0, find the value of the 2012 power of X
Observe the following equation in writing
(x-1) (x + 1) = the square of X-1
(x-1) (the square of X + X + 1) = the third power of X-1
(x-1) (the third power of X + the square of X + X + 1) = the fourth power of X-1
Make it clear

It is known that (x-1) (the third power of X + the square of X + X + 1) = the fourth power of X-1. It is also known that the third power of X + the second power of X + X + 1 = 0 to get the fourth power of X-1 = 0 to get x = 1 or x = - 1. When x = 1, the third power of X + the second power of X + X + 1 is not equal to 0. When x = - 1, the third power of X + the second power of X + X + 1 is discarded

Known: the third power of X + the square of X + X + 1 = 0, find the value of 1 + X + the square of X + the third power of X +... + the 2012 power of X

∵x³+x²+x+1=0
1 + X + the square of X + the third power of X +... + the 2012 power of X
=1+x(1+x+x²+x³)+x^5(1+x+x²+x³)+…… +x^2009(1+x+x²+x³)
=1+0+0+…… +0
=1

If the coefficient and constant of a quadratic trinomial of the letter X are 1 and the coefficient of the first term is − 12, then the quadratic trinomial is 1______ ．

For the quadratic trinomial of the letter X, if the coefficient of the quadratic term and the constant term are both 1 and the coefficient of the primary term is − 12, then the quadratic trinomial is x2 − 12x + 1

Please write a quadratic trinomial formula about X, which satisfies the following conditions: the quadratic term and the constant term are opposite to each other, and the coefficient of the primary term is negative one

X square minus x minus one

For example, the converse of the following proposition is a false proposition 1. If one digit of an integer is 5, then the integer can be divided by 5 2. If both angles are right angles, then the two angles are equal