If 3x + 7 = 40, what is 9x + 21 So what's the sum of three eighths times 3x + 7 plus four eleventh

If 3x + 7 = 40, what is 9x + 21 So what's the sum of three eighths times 3x + 7 plus four eleventh

3x+7=40
x=11
9x+21=9×11+21=120

7 / 9x-2 / 3x = 5 / 12, what is x equal to?

7/9x－2/3x＝5/12
1/9x=5/12
x=5/12÷1/9
x=15/4

Number a divided by number B, the quotient is 47, the difference between the two numbers is 21? (solved by equation)

Let B be x and a be 47x. X-47x = 21 & nbsp; 37x = 2137x × 73 = 21 × 73 & nbsp; & nbsp; & nbsp; X = 49; a be 47x = 47 × 49 = 28; a and B be 28 and 49 respectively

The sum of ABC's three numbers is 255. It is known that a divided by B and B divided by C are quotient 5. What are the three numbers a, B and C?
equation

A=5B+1
B=5C+1
A+B+C=5(5C+1)+1+5C+1+C=255
31C=248
C=8
B=41
A=206

A. The sum of B and C is 255. It is known that a divided by B, B divided by C is quotient 5, and 1a, B and C are less
Use the equation. Come on

Let C be X
B is 5x + 1
A is 25X + 6
x+5x+1+25x+6=255
x=8
therefore
C=8
B=41
A=206

The sum of ABC's three numbers is 412a divided by B and B divided by C. which of the three is the largest?
Also: given three numbers (no 0), add them together to get 2664, the largest minus the smallest de 495. What are the three numbers?
Three martial arts teams compete in the challenge arena. First, one player from each of the two teams will compete in martial arts. If there is only one team left, how many martial arts competitions will the team win?

“znj1998”：
(1) The three numbers are 29, 94 and 289 respectively,
(2) There are countless solutions to this problem, such as 1080, 999, 585
(3) The number of players in each team is unknown
Good luck and goodbye

Three times of a number divided by 5, the quotient is 4 and the remainder is 4. Let this number be X. what's wrong with the following equation?
A.（3X-4）÷5=4
B.3X-4×5=4
C.3X÷5-4=4
D.3X=4×5+4

（3X-4）÷5=4
The solution is x = 8, and four options C are incorrect

(1) What's the quotient of 3 / 4 minus the product of 2 / 3 and 9 / 10 and dividing by 3 / 5?

The product of 2 / 3 and 9 / 10 = 3 / 5
3 / 4 minus 3 / 5 = 3 / 20
3 / 20 divided by 3 / 5 = 1 / 4

7(3+X)=56
solve equations

7(x+3)=56
x+3=56/7=8
x+3=8
x=8-3
x=5

56 / (x + 4) + 56 / (x-4) = 7, then what is x equal to

56/(x+4) + 56/(x-4) =7
Multiply both sides by (x + 4) (x-4) / 7 to get:
8(x-4)+8(x+4)=(x+4)(x-4)
16x=x²-16
x²-16x=16
(x-8)²=80
x-8=±4√5
x=8±4√5