It is known that the solution of linear equation AX + B = 0 (a, B are constants, a ≠ 0) is x = 2, then when the function value of linear function y = ax + B is 0, the value of independent variable x is 0___ . It is known that the solution of linear equation AX + B = 0 (a, B are constants, a ≠ 0) is x = 2, then when the function value of linear function y = ax + B is 0, the value of independent variable x is -

It is known that the solution of linear equation AX + B = 0 (a, B are constants, a ≠ 0) is x = 2, then when the function value of linear function y = ax + B is 0, the value of independent variable x is 0___ . It is known that the solution of linear equation AX + B = 0 (a, B are constants, a ≠ 0) is x = 2, then when the function value of linear function y = ax + B is 0, the value of independent variable x is -

It is known that the solution of the equation AX + B = 0 (a, B are constants, a ≠ 0) is x = 2,
Then, when the value of the function y = ax + B is 0, the value of the independent variable x is [2]

If a zero point of the function f (x) = ax + B is 2, then what is the zero point of G (x) = BX - ax? Please explain it in detail

ax+b=0 ==> x=-b/a=2
BX square - AX = x (bx-a)
Let x (bx-a) = 0, then X1 = 0, X2 = A / b
∵-b/a=2
∴a/b=-1/2
The zeros of G (x) are 0 and - 1 / 2

Can X be equal to x?

Of course not. If it appears, you should check whether the equation listed above has been used twice
Let me give a simple example. For example, one equation is listed as x = 2Y, and another equation is listed as 4x = 8y. If you take the first one into the second one, you will get x = X. so your first formula is the same as the second one. If you don't understand, you can ask me in private