If a, B are opposite numbers and CD are reciprocal numbers, and the absolute value of M is 1, find 2014 (a + b) - CD + 2014m

If a, B are opposite numbers and CD are reciprocal numbers, and the absolute value of M is 1, find 2014 (a + b) - CD + 2014m

If a and B are opposite to each other, C and D are reciprocal to each other, and the absolute value of M is 1, find the value of (a + b) cd-2014m

According to the meaning of the question: a + B = 0, CD = 1, M = 1 or - 1, when m = 1, the original formula = - 2014; when m = - 1, the original formula = 2014

A math problem about absolute value in grade one of junior high school
|1/21-1/20|+|1/22-1/21|+|1/23-1/22|+...+|1/35-1/34|
What's the number

|1/21-1/20|+|1/22-1/21|+|1/23-1/22|+...+|1/35-1/34|
(if the denominator is larger, it will be smaller, so negative sign should be added before the absolute value is removed.)
=-1/21+1/20-1/22+1/21-1/23+1/22-...-1/35+1/34
=1/20-1/35
=3/140

It is known that: 2a-24 + (3a-b + k) * 2 = 0, if the value range of B is B < 0, then the value range of K is__ ?

｜2a-24｜>0
(3a-b + k) * 2 > 0 and ｜ 2a-24 + (3a-b + k) * 2 = 0
So 2a-24 = 0
(3a-b+k)*2＝0
So a = 12
36-b+k＝0
k=b-36
And because of B

If B satisfies 3A & sup2; + 5|b | = 7, s = 2A & sup2; - 3|b |, then the value range of real number s is

Because 3A & sup2; + 5 | B | = 7, we can see that a & sup2; and | B | = 0,
So 3A & sup2 can be obtained;

We know the inequality X & sup2; - (3a + 2) x + 2A (a + 2) about X

(1) If 3 &; m, 9 - (3a + 2) × 3 + 2A (a + 2) ≥ 0
　　2a²-5a+3≥0
　　(a-1)(2a-3)≥0
A ≤ 1 or a ≥ 3 / 2
　　(2) （x-2a）[x-(a+2)]

If the equation (a ^ 2-4) x ^ 2 + (2-3a) x + (a + 1) y + 3A = 0 is a quadratic equation of two variables, then the value of a is

If the equation (a ^ 2-4) x ^ 2 + (2-3a) x + (a + 1) y + 3A = 0 is a binary linear equation, then the value of a is ± 2
Then:
a²-4=0
a²=4
a=±2

In the equation (A's square-4) x's square + (2-3a) x + (a + 2) y + 3A = 0, if the equation is quadratic, then the value of a is ()
This is a multiple choice question, but because of the number of words required, so I did not write the answer!

Once
So the square of (A-4) x = 0
So the square of a - 4 = 0
A = 2 or - 2
If a = - 2
Then (a + 2) y = 0
So there's only x unknown
It's not a binary equation
So a = 2

Is the absolute value of any rational number nonnegative?

That's right

Known a

a4,|a|>4
a=4,|a|=4
-4