For positive numbers a, B, C and D satisfying ABCD = 16, what is the minimum value of a + B + C + D,

For positive numbers a, B, C and D satisfying ABCD = 16, what is the minimum value of a + B + C + D,

Because ABCD = 16, and they are all positive numbers, a + B + C + D is greater than or equal to 4 times the fourth root, ABCD = 8, so the minimum value of a + B + C + D is 8

If integer a > b > C > D and ABCD = 49, then the value of B D is?

B=3.5 D=1

Given that a, B, C and D are mutually unequal integers, and ABCD = 9, then the value of a + B + C + D is equal to ()
A. 0b. 4C. 8D

The four numbers are less than or equal to 9, and they are not equal to each other. From the product of 9, there must be 3 and - 3 in the four numbers. The four numbers are: 1, - 1, 3, - 3, and the sum is 0