If a: B = 5:3, B: C = 7:4, then a: B: C=

If a: B = 5:3, B: C = 7:4, then a: B: C=

He didn't do it right
A：B=5：3=35：21
B：C=7：4=21：12
So a: B: C = 35:21:12

If the values of 4x-7 and 5 (x + 5) are equal, then the value of X is A. - 9 B. - 5 C.3 D.1

4x-7=5（x+5）
4x-7=5x+25
5x-4x=-7-25
x=-32
The title is wrong

Int a [] = {1,2,3,4,5,6,7,88,9,10}, * P = a; then the expression of 3 is () a) P + = 2, * (P + +) b) P + = 2, * + + P C) P + = 3, * P
int a[ ]={1,2,3,4,5,6,7,88,9,10},*p=a;
The expression of 3 is ()
A) p+=2,*(p++) B) p+=2,*++p
C) p+=3,*p++ D) p+=2,++*p
What and why?

Choose a, after assigning the first address of the array to P, then * P = = 1, let it be 3, of course, he moves back two bits, that is, P + = 2, at this time * P = 3. As for the difference between * (P + +) and * (+ + P), P + + is to let P output first and then increase 1 by itself, and + + P is to let P increase 1 by itself and then output