The master and the apprentice process the same number of machine parts at the same time. When the master completes 50%, the apprentice takes 102 unfinished parts: when the master completes the task, the apprentice will finish the task The ratio of the number of parts processed by master and apprentice is 5:4?

The master and the apprentice process the same number of machine parts at the same time. When the master completes 50%, the apprentice takes 102 unfinished parts: when the master completes the task, the apprentice will finish the task The ratio of the number of parts processed by master and apprentice is 5:4?

Because the master and the apprentice process the same amount of the same machine parts at the same time, and when the master completes the task, the ratio of the number of parts processed is 5:4, so the apprentice's processing speed is 4 / 5 of the master's, and when the master completes half of the task, the apprentice should have left
1-50% × 4 / 5 = 3 / 5 parts are not finished. At this time, the apprentice has 102 pieces, so the total number of pieces is 102 △ 3 / 5 = 170, so the apprentice processes 170 × 4 / 5 = 136 pieces, and the master processes 170 pieces
Use the method of primary school!

The master and the apprentice make the same number of parts. When the master makes half of the parts, the apprentice has 180 left to finish
At that time, one fifth of the apprentices didn't do it. How many parts did the apprentices process

1－1/5＝4/5
4/5÷2＝2/5
1－2/5＝3/5
180 △ 3 / 5 = 300

The apprentice finished 40% of the total number of parts. The master processed 80 more parts than the apprentice. How many parts did the master process?
How did you get here

Suppose master processed a, there are n in total
be
a+（a-80）=n
a-80=40%n
Solution
a=240