6.5x-1 / 10 = 1 / 4

6.5x-1 / 10 = 1 / 4

6.5x-1 / 10 = 1 / 4
6.25x=0.1
x=0.016

(x^2+5x+5)^(5/2)+1=0,x=?

(x^2+5x+5)^(5/2)=-1,
There is no solution in the range of real number

How to calculate 5x + 5 (10-x) = 825

5x+50-5x=825
x= 770

2.5×8-0.5x=19.6

x=0.8

0.4 (3x minus 7) minus 0.5 (x minus 0.5) minus 0.2 x equals 10

0.4 (3x minus 7) minus 0.5 (x minus 0.5) minus 0.2 x equals 10
That is, 2 (3x-7) / 5-2 × (x-1 / 2) - 5x = 10
∴2×(3x-7)-10×(x-1/2)-25x=50
∴6x-14-10x+5-25x=50
∴-29x=59
∴x=-59/29

3x/0.5-(7*0.2-x)/0.4=1
Urgent!

The answer should be 9 / 17

9X+0.4【2.5(3X-4)+10】=6/7【14(X+1)-28】

9X+0.4【2.5(3X-4)+10】=6/7【14(X+1)-28】
Remove the brackets on both sides to get 9x + 0.4 * 2.5 (3x-4) + 0.4 * 10 = 6 / 7 * 14 (x + 1) - 6 / 7 * 28
That is 9x + (3x-4) + 4 = 12 (x + 1) - 24
Remove the brackets on both sides to get 9x + 3x-4 + 4 = 12x + 12-24
It is reduced to 12x = 12x-12
Subtract 12x from both sides to get 0 = - 12
So the original equation has no solution

0.5(x-4)-(3x+4)=-7.5

0.5(x-4)-(3x+4)=-7.5
0.5x-2-3x-4=-7.5
3x-0.5x=7.5-2-4
2.5x=1.5
x=0.6

3 ^ x = 2 ^ x, find x.5 ^ (x-1) · 10 ^ 3x = 8 ^ x, find X

3^x=2^x
Divide by 2 ^ x
(3/2)^x=1
x=0
5^(x-1)*10^3x=8^x
5^(x-1)*(5*2)^3x=5^(x-1)*5^3x*2^3x=(2^3)^x
So 5 ^ (x-1) * 5 ^ 3x = 1
5^(x-1+3x)=5^0
x-1+3x=0
x=1/4

1/x(X+2)+1/(X+2)(x+4)+.1/(x+8)(x+10)=1/3x

X=5
All the formulas are reduced to 1 / (x + 2) (x + 4) = {1 / (x + 2) - 1 / (x + 4)} / 2
The original equation is equal to 10 / X (x + 10) = 2 / 3x
Square of x = 5x
X is not equal to 0, so x = 5