Finding the derivative of (1 / LNX)
(1/lnx)' = -1/ln²x * (lnx)' = -1/ln²x * 1/x = - 1/(xln²x)
-The derivative of LNX
(-1/lnx)'=1/[x*(lnx)^2] ;
[-ln(1/x)]'=1/x;
I don't know which one you want
The derivative of TXT. F (x) = (LNX) + A ^ (3x)
F '(x) = 1 / x + 3 (a ^ x) LNA
The most important is: A ^ x = (a ^ x) LNA