It is proved that LIM (x → x0) x & # 178; = (x0) &# 178;

It is proved that LIM (x → x0) x & # 178; = (x0) &# 178;


The key step is the key step of the key step, we assume that \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\when0 <| x-x0 <δ, there is | x ∧ 2-x0 ∧ 2 <Ε



How to calculate LIM (x - > 1) (x ^ 2-6x + 8) / (x ^ 2-5x + 4)?


The result is infinite



x→2(X^2-5X+6)/(X^2-6X+8)


Original formula = (X-2) (x-3) / (X-2) (x-4) = (x-3) / (x-4)
So the limit = (2-3) / (2-4) = 1 / 2