How many tons is 20 50kg

How many tons is 20 50kg

1 ton

Simplification (a ^ m + B ^ n) (a ^ 2m + B ^ 2n) (a ^ M-B ^ n)

(a^m+b^n)(a^2m+b^2n)(a^m-b^n)
=(a^2m-b^2n)(a^2m+b^2n)
=a^4m-b^4n
(using the square difference formula)

Fractional addition and subtraction: simplification: 2m / m-n-n / N-M + m + 2n / N-M

2-n-1-m+m+2-m
=3-m-n

(M + 2n) square (2n-m) square

The original formula = (2n + m) &# 178; (2n-m) &# 178;
=[(2n+m)(2n-m)]²
=(4n²-m²)²
=16n^4-8m²n²+m^4

Square of (M + 2n) - (m-n) square
Factorization

(m+2n)^2 -(m-n)^2
= m^2+4mn + 4n^2 - m^2+2mn-n^2
= 6mn+3n^2
=3n(2m+n)

Calculation: (M + 2n-p) 2

The original formula = [(M + 2n) - P] 2, = (M + 2n) 2-2p (M + 2n) + P2, = M2 + 4Mn + 4n2-2pm-4pn + P2

Square of (m-2n) - 2 (m-2n) (M + 2n) + (M + 2n) =?

Original form
=[(m-2n)-(m+2n)]²
=(-4n)²
=16n²

The square of (m-2n + 2)

（m-2n+2)^2
=[(m-2n)+2]^2
=(m-2n)^2+4(m-2n)+4
=m^2-4mn+4n^2+4m-8n+4

Uniform circular motion. 1, the centripetal acceleration is equal to the square of the linear velocity divided by the radius. 2, the centripetal acceleration is equal to the square of the angular velocity multiplied by the radius
Formula 1 indicates that the centripetal acceleration is inversely proportional to the radius, and formula 2 indicates that the centripetal acceleration is directly proportional to the radius?

Formula 1 shows that the centripetal acceleration is inversely proportional to the radius, and the condition is that the linear velocity remains unchanged
Formula 2 shows that the centripetal acceleration is proportional to the radius, and the condition is that the angular velocity remains unchanged

If n satisfies the square of (n-2006) + (2008 + n) = 1, find the value of (2008-n) (n-2006)

Let n-2006 = a, 2008-n = B
a^2+b^2=1 ==> (a+b)^2=a^2+b^2+2ab=1+2ab =(n-2006+2008-n)^2=2^2=4
2ab=3
ab=3/2
2008 minus n times n minus 2006 = 3 / 2