Is p = ρ GH formula applicable to all liquid containers? For example, the water in a semicircular bowl, the oil in a funnel that blocks the mouth, The derivation of P = ρ GH P = g / S =mg/s =ρvg/s Because V / S = H So p = ρ GH But when v / S = h does not hold, as in the above two examples, P = ρ GH

Is p = ρ GH formula applicable to all liquid containers? For example, the water in a semicircular bowl, the oil in a funnel that blocks the mouth, The derivation of P = ρ GH P = g / S =mg/s =ρvg/s Because V / S = H So p = ρ GH But when v / S = h does not hold, as in the above two examples, P = ρ GH

It is true for any container. The liquid pressure is only related to the depth. If we follow the idea of the landlord, we should pay attention to one point. The so-called pressure is for a certain place. The formula of V / S = h is also relative to a certain place. For example, if you want to calculate the pressure on the bottom plane of the bowl, you can circle the bottom of the bowl to simulate a

The formula P = ρ GH for all deformations

h=p/pg
p=p/gh

Formula deformation P = ρ GH
P = ρ GH, then what is h

h=p/ρg