To make the output value y greater than 100, what is the minimum positive integer x? Even number * 5 of positive integer equals output y; odd number * 5 + 13 of positive integer x equals output y

To make the output value y greater than 100, what is the minimum positive integer x? Even number * 5 of positive integer equals output y; odd number * 5 + 13 of positive integer x equals output y

If the input x is odd
Then 5x + 13 = Y > 100
5X+13＞100
X > 87 / 5 = 17.4, because x is a positive integer and odd, so x = 19
If the input x is even
Then y = 5x > 20
Because x is a positive integer and even, x = 22
So the minimum input x is 19
If you have any questions, you can go to Baidu Hi

To make the output value y greater than 100, what is the minimum positive integer x? Even number * 5 of positive integer equals output y; odd number * 4 + 13 of positive integer x equals output y

Let even number be 2n and odd number be 2n + 1
5*2n=(2n+1)*4 n=2
n> 2, the "output value of even number" is larger than the "output value of odd number 1 larger than it"
N = 20 output 100 N = 21 output 97 n = 22 output 110
So the minimum positive integer is 22

As shown in the figure, to make the output value y greater than 100, the input minimum positive integer x is______ ．

If x is an even number, according to the meaning of the problem, we get x × 4 + 13 > 100, the solution, we get x > 874, so the minimum integer value of X is 22; if x is an odd number, according to the meaning of the problem, we get x × 5 > 100, the solution, we get x > 20, so the minimum integer value of X is 21, in conclusion, the minimum positive integer value of X is 21

In a positive integer, what is the difference between the sum of the first 100 even numbers and the sum of the first 100 odd numbers?

100

1,2,3,… Among these n positive integers, there are a prime number, B composite number, P odd number and Q even number. (P-A) - (B-Q) =?

Let x prime numbers exist in odd numbers
Then there is a composite P-X in the odd number
p-x+q=b .(1)
x+1=a .(2)
x=a-1
p-a+1+q=b
(p-a)-(b-q)=-1

In the n positive integers of 1,2,3... N, we know that there are p prime numbers, Q composite numbers, K odd numbers and m even numbers, then what is (q-m) + (P-K)?

Equal to - 1
（Q-M）+（P-K）=(Q+P)-(M+K)
Because 1 is neither a prime nor a composite, q + P = n-1
And M + k = n
So the value of the original formula is - 1

In positive integers 1 to 20, there are () odd numbers, () even numbers, () prime numbers, and () combined numbers
This question appeared in "new ideas guidance and training". There are 12 in total. Is it a wrong number or something?

Ha ha! It's obviously wrong. The reasons are as follows:
Composite number: natural number divided by 1 and it has other factors. For example, 6 can be divided by 1 and 6, 2 and 3
The total number of positive integers 1 to 20 is (4,6,8,9,10,12,14,15,16,18,20) 11
Hope the answer is useful to you!

Let n denote any integer, and use the formula containing n to express: what are three continuous even numbers and three continuous odd numbers

Even numbers are 2n-2.2n.2n + 2
The odd number is 2n-3.2n-1.2n + 1

Let n denote any integer, and use the formula containing n to denote: (1) any even number (2) any odd number

(1) Any even number
2n
(2) Any odd number
2n - 1 or 2n + 1

A + B = C + D, a * BC + D + 100, AB * cd-a * b * c * d = 1000, a and B are odd numbers, C and D are even numbers?

a=1
b=9
c=6
d=4