High number for limit! Lim x tends to 0 (SiNx / x) ^ 1 / 2

High number for limit! Lim x tends to 0 (SiNx / x) ^ 1 / 2

When x approaches 0, SiNx is equivalent to x, so the answer is 1

High number for limit, experts to enter
lim(x→0+)[e^x-e^(1/x)]/[e^(-1)-e^(1/x)]

The above and below of the original formula are multiplied by e ^ (- 1 / x) at the same time,
The original formula = Lim [e ^ (x-1 / x) - 1] / [e ^ (- 1-1 / x) - 1]
=(0-1)/(0-1)
=1

Seek the limit, don't answer indiscriminately if you don't know
What is the limit of (COT x) ^ 2-1 / x ^ 2 when x approaches 0
The answer is - 2 / 3

Lim [x → 0] (COT & # 178; X - 1 / X & # 178;) = Lim [x → 0] (1 / Tan & # 178; X - 1 / X & # 178;) general division = Lim [x → 0] (X & # 178; - Tan & # 178; x) / (X & # 178; Tan & # 178; x) denominator with Equivalent Infinitesimal Substitution = Lim [x → 0] (X & # 178; - Tan & # 178; x) / X & # 8308; lobita's law = lim