lim(x->0) (sin2x)/(tan2x) 2/3

lim(x->0) (sin2x)/(tan2x) 2/3


lim(x→0)sin2x/tan2x=lim(x→0)cos2x=1
as sure as a gun!



"Urgent!"... Calculus.. LIM (LNX / x) x - > 0 how much is lim
LIM (INX/X)
x->0


Negative infinity



Calculus LIM (x → 1) | - X-1 | - X-1=


lim(x→1+)|x-1 |\(x-1)=1
lim(x→1-)|x-1 |\(x-1)=-1



The general solution of Y '' '- 8y = 0 differential equation


Characteristic equation R ^ 3-8 = 0
(r-2)(r^2+2r+4)=0
r=2,-1±√3i
So the general solution is: y = C1E ^ (2x) + e ^ (- x) [c2sin (√ 3x) + c3cos (√ 3x)]



A special solution of Y "- 9y = cos3x-sin3x can be set as____________


A special solution of Y "- 9y = cos3x-sin3x ① can be set as y = acos3x + bsin3x, then y '= - 3asin3x + 3bcos3x, y' '= - 9acos3x-9bsin3x, substituting into ①, - 18acos3x-18bsin3x = cos3x-sin3x, the comparison coefficient is - 18a = 1, - 18B = - 1, the solution is a = - 1 / 18, B = 1 / 18



1. The general solution of the differential equation y "- 9y = 3x & # needs to be solved urgently


Characteristic equation R ^ 2-9 = 0
r1=3 r2=-3
Let y * = ax ^ 2 + BX + C
y*'=2ax+b
y*''=2a
So - 9A = 3 - 9b = 0, 2a-9c = 0
a=-1/3 b=0 c=2a/9=-2/27
Therefore, the general solution is y = C1E ^ 3x + c2e ^ (- 3x) - (1 / 3) x ^ 2 - (2 / 27)



Higher order differential equation y '''y '' = 2
The general solution that the third derivative of Y multiplied by the second derivative of Y equals 2





Do you want to solve the differential equation?
Do you want to solve the first and second order differential equations


Test, and generally there will be questions, either fill in the blanks or big questions



Differentiate y= 1000000 * (1.6 ^ (0.25x))
Differential equation:
Differentiate y= 1000000 * (1.6 ^ (0.25x))
1 day ago - 1 week left to answer.


y = 1000000×[1.6^(¼x)]= 1000000×e^{ln[1.6^(¼x)]}= 1000000×e^[(¼x)ln1.6]dy/dx = 1000000×{e^[(¼x)ln1.6]}×¼ln1.6= 250000×{e^[(¼x)ln1.6]}×ln1.6= 250000×[1...



A general solution to the square of Y '= (x + y)
Let u = x + y


Let t = x + y, then y '= DT / DX-1 ∫ DT / DX-1 = T & sup2; = = > DT / DX = T & sup2; + 1 = = > DT / (T & sup2; + 1) = DX = = > arctant = x + C (C is an integral constant) = = > t = Tan (x + C) = = > x + y = t