Give m exercise books to n students, if each student has 3 exercise books, then the remaining 80; if each student has 5 exercise books, then the last student has less than 5 exercise books, and the value of n is --- 41 or 42 The result is n > 40, why 41 or 42 The formula is as follows: from the meaning of the title, 3n+80=m m-5（n-1）

Give m exercise books to n students, if each student has 3 exercise books, then the remaining 80; if each student has 5 exercise books, then the last student has less than 5 exercise books, and the value of n is --- 41 or 42 The result is n > 40, why 41 or 42 The formula is as follows: from the meaning of the title, 3n+80=m m-5（n-1）

Suppose 3N + 80-5 (n-1) = 4, 3N + 80-5 (n-1) = 3, 3N + 80-5 (n-1) = 2, 3N + 80-5 (n-1) = 1
Then four values of N can be obtained respectively, only two of which are integers

Mr. Li distributed a stack of exercise books to the first group of students. Each group had five more than 23, and each group had seven more than 7. How many students are there in the first group? How many exercise books are there in the first group
How many copies are there?
The formula!

Double profit problem in profit and loss problem
5 per person, 23 more
7 per person, 7 more
Number of people: (23-7) / (7-5) = 8
Exercise book: 8 × 5 + 23 = 63

Give n exercise books to several students. If each student has 3 exercise books, the rest will be 8; if each student has 5 exercise books, the last student will have exercise books, but not enough
5, then what is the value of N

There are x people, and the last one has y exercise books,
So 0 < y < 5
3x+8=n
5（x-1）+y=n
therefore
3x+8=5（x-1）+y
Solution
x=(13-y)/2
Because x is an integer and 0 < y < 5
So y = 1 or 3
So x = 6 or 5
When x = 6, y = 1
N = 3 times 6 + 8 = 26
N = 5 times (6-1) + 1 = 26
When x = 5, y = 3
N = 3 times 5 + 8 = 23
N = 5 times (5-1) + 3 = 23
So the value of n is 26 or 23
There are six or five classmates