There are two equal forces F1 and 2. When the angle between them is 90 degrees, the resultant force is F. when the angle between them is 60 degrees, the resultant force is f_ RT, I figured it out to be 1.5f1 ^ 2 The answer is (√ 6 / 2) F

There are two equal forces F1 and 2. When the angle between them is 90 degrees, the resultant force is F. when the angle between them is 60 degrees, the resultant force is f_ RT, I figured it out to be 1.5f1 ^ 2 The answer is (√ 6 / 2) F

According to the parallelogram rule
When the angle is 90 degrees, it is a square
Then √ 2F1 (or √ 2F2) = f
F1=F2=√2/2F
Consider another case
When the included angle is 60 degrees, it is a rhombus according to the parallelogram rule, and the included angle is 60 degrees
So from the geometric relationship (it's better to draw a picture)
F = 3f1 (or F2) = (√ 6 / 2) f