Let Sn be the sum of the first n terms of positive sequence [an], 4sn = an ^ 2 + 2an-3. Given BN = 2 ^ n, find the value of TN = A1B1 + a2b2 +... + anbn

Let Sn be the sum of the first n terms of positive sequence [an], 4sn = an ^ 2 + 2an-3. Given BN = 2 ^ n, find the value of TN = A1B1 + a2b2 +... + anbn

An = 2n-3 or an = 2n + 1
TN = 10 + (2n-5) 2 ^ n + 1) or TN = 2 + (2n-1) 2 ^ (n + 1)
^Denotes the power of several

The product of three continuous natural numbers is 336. The three numbers are______ 、______ 、______ ．

336 = 2 × 2 × 2 × 3 × 7 = 8 × 6 × 7, so the three natural numbers are 6, 7 and 8 respectively

The product number of five continuous natural numbers is 1520. How to find these five numbers?

The quality factor of 1520 is: 1
1520=2×2×2×2×5×19,
∵ the product of five continuous natural numbers must be an integral multiple of 120,
11520 is not an integral multiple of 120, so it should not be 1520