With 0, 1, 2 three numbers can form a lot of natural numbers, which are arranged from small to large, respectively: 0, 1, 2, 10... Then 2012 is the number one

With 0, 1, 2 three numbers can form a lot of natural numbers, which are arranged from small to large, respectively: 0, 1, 2, 10... Then 2012 is the number one

We can define a ternary system, such as 1 for 1; 2 for 2; 10 for 3; 11 for 4 100 means 3 ^ 2 = 9; so we see that the number of 2012 is 2x3 ^ 3 + 0x3 ^ 2 + 1x3 + 2 = 54 + 3 + 2 = 59, because we have to count 0, so 2012 is the 60th number. The answer upstairs is correct. I don't know how to do it. Is it a number?

How many 4-digit permutations are there from the 10 natural numbers 0-9? How to calculate

There are 9 methods for the highest bit and 10 methods for the other bits, so there are 9 × 10 ＾ 3 methods

Given that the product of three continuous natural numbers is 60, how to calculate the sum of these three natural numbers

With short division, 60 is decomposed into 2 * 2 * 3 * 5, because it is a continuous natural number, there are 3 and 5, 2 * 2 = 4, so it is 3 + 4 + 5 = 12