The domain of the function y = 1 / 1-tan2x is

The domain of the function y = 1 / 1-tan2x is

y=1/1-tan2x；
∴1-tan2x≠0
And 2x ≠ π / 2 + K π
Ψ tan2x ≠ 1 and X ≠ π / 4 + K π / 2
Ψ 2x ≠ π / 4 + K π and X ≠ π / 4 + K π / 2
The domain of definition is {x | x ≠ π / 8 + K π / 2 and X ≠ π / 4 + K π / 2}

The definition field of function y = √ tan2x is

First, tan2x is greater than 0
Secondly, tan2x is meaningful, that is, 2x ≠ K π + 1 / 2 π
It can be solved simultaneously

Finding the domain of definition of function y = (1 / (tan2x))

Tan2x! = 0 gets 2x! = KPAI X! = KPAI / 2
2x!=(2k+1)*pai/2 x1=（2k+1)*pai/4
So x! = KPAI / 4
(PAI refers to the one on 3.14, understanding!)