Given that f (x) = 2 / (3 ^ X - 1) + m is an odd function, find the value of the constant M Given that f (x) = 2 / (3 ^ X - 1) + m is an odd function, find the value of the constant M It's the X of three, minus one

Given that f (x) = 2 / (3 ^ X - 1) + m is an odd function, find the value of the constant M Given that f (x) = 2 / (3 ^ X - 1) + m is an odd function, find the value of the constant M It's the X of three, minus one

Because f (x) is an odd function, f (- x) = - f (x) is: 2 / (3 ^ (- x) - 1) + M = - (2 / (3 ^ x-1) + m) 2 / (3 ^ (- x) - 1) + M = - 2 / (3 ^ x-1) + m2 / (1 / 3 ^ x-1) + 2 / 3 ^ X-1 = 2m, there are: 2 / (3 ^ x-1) - 2 * 3 ^ X / (3 ^ x-1) = - 2M2 (1-3 ^ x) / (3 ^ x-1) = - 2m, so m = 1

If the odd function f (x) = x + MX2 + NX + 1 defined on (- 1,1) is an odd function, then the values of constants m and N are ()
A. m=0，n=1B. m=1，n=1C. m=0，n=0D. m=1，n=1

∵ f (x) = x + MX2 + NX + 1 is an odd function defined on (- 1,1), then f (x) = XX2 + NX + 1, then f (− 12) 2 − 12n + 1 + 12 (12) 2 + 12n + 1 = 0 is obtained from F (− 12) + F (12) = 0, and N = 0 is obtained

Given x + y = 4, xy = - 2, find the value of algebraic formula 3 (XY + 2Y) - (xy-6x)

Original formula = 3xy + 6y-xy + 6x
=2xy+6(x+y)
=2*(-2)+6*4=24-4=20