In the expansion of (1 + 2x) 6, the coefficient of X4 is______ ．

In the expansion of (1 + 2x) 6, the coefficient of X4 is______ ．

The general term of the expansion is tr + 1 = 2rc6rxr, let r = 4, the coefficient of X4 in the expansion is 24C64 = 240, so the answer is: 240

If - A / 2x ^ | m | y is the monomial of X and y, and the coefficient is - 5 and the degree is 5, then a=_ ,m_?

Coefficient - A / 2 = - 5
a=10
The number of times y is 1
therefore
|m|=5-1=4
M = 4 or - 4

(1) In the equation y = KX + B, given x = - 3, B = - 2, y = - 10, find the absolute value of K (2) 2x + 5 = 1
（1）3x-2=3（4x-5）
（2）2.4y-3.12=1.2（y+4.1）
(3) 2X of 6-5-3x of 2 + 1 = 1
(4) 2X of 0.2 + X-7 of 3-0.5 = 5

(1) Because in the equation y = KX + B, x = -- 3, B = -- 2, y = -- 10,
So -- 10 = -- 3K -- 2
3k=8
k=8/3.
(2) I2x+5I=1
2X + 5 = 1 or 2x + 5 = -- 1
So X1 = -- 2, X2 = -- 3
(1) 3x--2=3(4x--5)
3x--2=12x--15
3x--12x=--15+2
--9x=--13
x=13/9.
(2) 2.4y--3.12=1.2(y+4.1)
2.4y--3.12=1.2y+4.92
2.4y--1.2y=4.92+3.12
1.2y=8.04
y=6.7.
(3) (2x--5)/6--(3x+1)/2=1
(2x--5)--3(3x+1)=6
2x--5--9x--3=6
2x--9x=6+5+3
--7x=14
x=--2.
(4) (2x+3)/0.2--(x--7)/0.5=5
5(2x+3)--2(x--7)=5
10x+15--2x+14=5
10x--2x=5--15--14
8x=--24
x=--3.