When factoring a quadratic trinomial, student a misinterprets the coefficient of the first term and decomposes it into 2 (x-1) (X-9), while student B misinterprets the constant term and decomposes it into 2 (X-2) (x-4). Please judge the correct quadratic trinomial and decompose it correctly

When factoring a quadratic trinomial, student a misinterprets the coefficient of the first term and decomposes it into 2 (x-1) (X-9), while student B misinterprets the constant term and decomposes it into 2 (X-2) (x-4). Please judge the correct quadratic trinomial and decompose it correctly

2 (x-1) (X-9) = 2x2-20x + 18, 2 (X-2) (x-4) = 2x2-12x + 16; because student a misread the coefficient of the first term and student B misread the constant term, the correct quadratic trinomial is: 2x2-12x + 18; then factor it into 2x2-12x + 18 = 2 (x-3) 2

When factoring a quadratic trinomial, student a misinterprets the coefficient of the first term and decomposes it into 2 (x-1) (X-9), while student B misinterprets the constant term and decomposes it into 2 (X-2) (x-4). Please judge the correct quadratic trinomial and decompose it correctly

2 (x-1) (X-9) = 2x2-20x + 18, 2 (X-2) (x-4) = 2x2-12x + 16; because student a misread the coefficient of the first term and student B misread the constant term, the correct quadratic trinomial is: 2x2-12x + 18; then factor it into 2x2-12x + 18 = 2 (x-3) 2

It is known that x ~ 2 + ax-12 can be decomposed into the product of a factor of two integer coefficients, then the number of qualified integers a is
It is known that x ~ 2 + ax-12 can be decomposed into the product of a factor of two integer coefficients, then the number of qualified integers a is
2 is the square of X

Because - 12 can be written as
（-1）*12、（-2）*6、（-3）*4、（-4）*3、（-6）*2、（-12）*1
So the value of a can be taken as: - 11, - 4, - 1, 1, 4, 11