The sum of the first n terms of sequence an is SN. For N, it belongs to positive integer, and (n, Sn) is on the function f (x) = 2x ^ 2-x, Let CN = 2 / Anan + 1, tn be the sum of the first n terms of a sequence, and let tn be

The sum of the first n terms of sequence an is SN. For N, it belongs to positive integer, and (n, Sn) is on the function f (x) = 2x ^ 2-x, Let CN = 2 / Anan + 1, tn be the sum of the first n terms of a sequence, and let tn be

(n, Sn) are all on the function f (x) = 2x ^ 2-x,
That is, Sn = 2n ^ 2-n
an+1=Sn+1-Sn=[2(n+1)^2-(n+1)]-(2n^2-n)=4n+1
an=4(n-1)+1
cn=2/[(4(n-1)+1)(4n+1)]=1/2{1/[(4(n-1)+1)]-1/[(4n+1)]}
Tn=1/2{1 - 1/[(4n+1)]}
=2n/(4n+1)
When m = 10
Tn=2/(4+1/n)9/20=m/20
So the minimum positive integer m = 10