(3) It is known that X / (x 2 + x 2 + 1) = 1 / 4, x 2 / (x 4 + x 2 + 1)

(3) It is known that X / (x 2 + x 2 + 1) = 1 / 4, x 2 / (x 4 + x 2 + 1)

x/(x2＋x＋1)＝1/4
4x=x²+x+1
3x=x²+1
Square on both sides:
9x²=x^4+2x²+1
∴x^4+x²+1=8x²
∴x2/(x4＋x2＋1)=x²/8x²=1/8

If the ratio of the roots of the equation a times the square of X + BX + C = 0 (a ≠ 0) is constant K, then the relationship among the coefficients a, B and C is
There's more.
Let the big root of the square-1997 * 1999x-1 = 0 of equation (1999x) be a, and the small root of the square-1998x-1999 = 0 of equation x be B, then a-b=

X2 / X1 = kx2 = kx1 Veda theorem X1 + x2 = - B / ax1x2 = C / a so X1 + x2 = X1 + kx1 = - B / ax1 = - B / a (K + 1) x1x2 = kx1 & # 178; = C / a so k * [- B / a (K + 1)] &# 178; = C / AB & # 178; K / A & # 178; (K + 1) &# 178; = C / a so B & # 178; k = AC (K + 1) &# 178;

If 2 is a root of the equation x squared - C = 0, what is the constant C? Can you get other roots of the equation

X ^ 2 - C = 0, x ^ 2 = C, x = - radical (c) or x = radical (c) = 2,
The other root of C = 4 is x = - 2