Using logarithm: 2 ^ 5A = 5 ^ 3B = 10 ^ 2C, find the formula between a.b.c

Using logarithm: 2 ^ 5A = 5 ^ 3B = 10 ^ 2C, find the formula between a.b.c

Let 2 ^ 5A = 5 ^ 3B = 10 ^ 2C = K
Then there are:
5a=log2(k)
3b=log5(k)
2c=lg(k)
So:
a=[log2(k)]/5=[lg(k)/lg2]*(1/5)
b=[log5(k)]/3=[lg(k)/lg5]*(1/3)
c=[lg(k)]/2
So:
15c^2=4ab
I hope you are satisfied with my answer

3x + 4Y = 11 how many groups are there in the range of positive integers

Choose C
y=11/4-3/4x
11/4-3/4x>0
x

Please help to find the values of integers a, B, C satisfying (8 / 25) ^ (- a) * (9 / 2) ^ (- b) * (5 / 3) ^ (- C) = 18
It is helpful for the responder to give an accurate answer

（8/25）^（-a）*(9/2)^(-b)*(5/3)^(-c)=18,
18 = 2*3^2 = [(25/8)^a][(2/9)^b][(3/5)^c]
= [5^(2a-c)][3^(c-2b)][2^(b-3a)]
2a - c = 0
c - 2b = 2
b - 3a = 1,
a = -1,
b = -2,
c = -2.

Given that a, B, C and D are mutually unequal integers, and ABCD = 9, then the value of a + B + C + D is equal to ()
A. 0b. 4C. 8D

The four numbers are less than or equal to 9, and they are not equal to each other. From the product of 9, there must be 3 and - 3 in the four numbers. The four numbers are: 1, - 1, 3, - 3, and the sum is 0

Let a = {x L x is a positive integer less than 9}, B = {1,2,3}, C = {3,4,5,6}, find a ∩ (B ∪ C), a ∪ (B ∩ C)

According to the meaning of the title, B ∪ C = {1,2,3,4,5,6} because a = {x | x}

Let a = {x} X be a positive integer less than 9} B = {1.2.3} C = {3.4.56} for Au (BNC), the answer is not important,

Let a = {x | x ≤ - 2 or x > 5}, B = {x | 1}

1. AUB = {x | x ≤ - 2 or x > 1};
2、A∩B={x|57}；
4. Au (CRB) = {x | x ≤ 1 or x > 5}
This kind of problem is generally analyzed and studied with the help of number axis

How to prove the set association law (AUB) UC = Au (BUC)

X ∈ left, that is, X ∈ AUB or X ∈ C
That is, X ∈ a or X ∈ B or X ∈ C
That is, X ∈ a or X ∈ B ∪ C
That is, X ∈ right
Explain that the left is contained in the right
Similarly, it can be proved that the right is contained in the left
So left = right

It is known that the complete set u is a real number r, a = (x / 1 "X" 4), B = (x / x2) to find AUB, Au (CCB), CC (AUB)

A={x | 1≤x≤4},B={x | x2}
be
A∪B={x | x

Let AB be two random events, then (AUB) (- au-b) denotes

(AUB) (- au-b) means the probability of occurrence of a or B multiplied by the probability that a does not occur or that B does not occur
Hope to adopt