Delete all complete square numbers in positive integer sequence 1, 2, 3, etc., and get a new sequence. The 2005 term of the new sequence is?

Delete all complete square numbers in positive integer sequence 1, 2, 3, etc., and get a new sequence. The 2005 term of the new sequence is?

In the positive integer sequence, item 2005 was originally: 2005
The complete square numbers adjacent to it are: 44 * 44 = 1936 and 45 * 45 = 2025
Therefore, after removing the first 44 perfect squares, the 2005 term is
2005+44＝2049>2025
Therefore, we need to remove 2025 to get the 2005 term of the new sequence
That is, the 2005 term of the new sequence is 2049 + 1 = 2050

Positive integers 1,2,3 Remove the complete square number and complete cube number in the sequence, and do not change the order, what is the number 2009?

44²=1996
45²=2025
12³=1728
13³=2197
1--2009,
There are 44 squares and 12 cubes
It's both square and cubic,
2^6,3^6,
There are 44 + 12-2 = 52 removed
2009 + 52 = 2061, of which 2025 is the square, and we need to remove it
2061+1=2062
Of the rest, 2009 is 2062

Delete all the complete square numbers in the positive integer sequence {n}, and get a new sequence. The item 2009 of this sequence is?
n=2054

Let the item 2009 of the new sequence be n, and there are x complete squares before the number n
2009+X>=X^2
The result is -44.32