Given that the polynomial (a + 3) x ^ 3-2x ^ 2Y + y ^ 2 - (5x ^ 3 + y ^ 2 + 1) does not contain x ^ 3 term, calculate the value of a ^ 3-2a ^ 2 + 4a-1

Given that the polynomial (a + 3) x ^ 3-2x ^ 2Y + y ^ 2 - (5x ^ 3 + y ^ 2 + 1) does not contain x ^ 3 term, calculate the value of a ^ 3-2a ^ 2 + 4a-1

Known polynomial (a + 3) x ^ 3-2x ^ 2Y + y ^ 2 - (5x ^ 3 + y ^ 2 + 1)
=（a-2)x^3-2x^2y-1
Does not contain x ^ 3 items in
So, A-2 = 0
a=2
So, a ^ 3-2a ^ 2 + 4a-1
=2^3-2*2^2+4-1
=8-8+8-1
=7

If the fourth power of 2x - the third power of 3x + the second power of AX + 7x + B can be divided by the second power of X, the value of a / B can be obtained
Can we set the other term as (2x + ax + b)? I need projects like that
Which term is x-square + X-2

If the fourth power of 2x - the third power of 3x + the second power of AX + 7x + B can be divided by x power + X-2, the value of a / B can be obtained
∵x²+x-2=0
(x+2)(x-1)=0
∴x=-2 x=1
Dai Rende:
32+24+4a-14+b=0 4a+b=-42
2-3+a+7+b=0 a+b=-6
∴a=-12
b=6
∴a/b=-12/6=-2

Let the polynomial 2x ^ 4-x ^ 3 + ax ^ 2 + 3x + B be divisible by x ^ 2-2x + 2, and find the value of a and B

Let 2x ^ 4-x ^ 3 + ax ^ 2 + 3x + B = (x ^ 2-2x + 2) (2x & # 178; + MX + B / 2), then 2x ^ 4-x ^ 3 + ax ^ 2 + 3x + B = (x ^ 2-2x + 2) (2x & # 178; + MX + B / 2) 2x ^ 4-x ^ 3 + ax ^ 2 + 3x + B = 2x ^ 4 + MX ^ 3-4x ^ 3 + B / 2x ^ 2-2mx ^ 2 + 4x & # 178; - BX + + 2mx + b2x ^ 4-x ^ 3 + ax ^ 2 + 3x + B = 2X ^ 4 + (M-4)

If 3x * x * x + m * x * x + n * x + 42 is divisible by X * x-5x + 6, then M + n = ()
Such as the title

Because 3x * x * x + m * x * x + n * x + 42 can be divided by X * x-5x + 6,
And x ^ 2-5x + 6 = (X-2) (x-3),
So when x = 2 or x = 3 is substituted into a polynomial, the result should be equal to 0,
So there are
24+4m+2n+42=0,
81+9m+3n+42=0,
It's very simple,
2m+n=-33,(1)
3m+n=-41,(2)
(2) - (1) get
m=-8,
So n = - 17,
So m + n = - 8 + (- 17) = - 25