If (A-2) x + (B + 1) y = 13 is a quadratic equation with respect to X and y, then a and B satisfy______ Conditions

If (A-2) x + (B + 1) y = 13 is a quadratic equation with respect to X and y, then a and B satisfy______ Conditions

∵ (A-2) x + (B + 1) y = 13 is a bivariate linear equation about X, y, ∵ a − 2 ≠ 0b + 1 ≠ 0, the solution is a ≠ 2, B ≠ - 1

Given a binary linear equation system 40 (x + y) = 400, 200 (x − y) = 400, try to write an application problem according to the quantitative relationship of the given equation system and solve it

The distance between a and B is 400 meters. Snails a and B start from a and B respectively and meet in 40 minutes. If the two snails go in the same direction, it will take 200 minutes for a to catch up with B. what's the speed of snails a and B? Let the speed of snail A and snail B be x m / min and Y M / min respectively

Solving binary linear equations {x + y = 164.8x/60 + 12Y / 60 = 1.88

X+Y=16
2\25X+1\5X=1.88
X+5\2Y=23.5
X+Y=16
Y=5
X=11

As shown in the figure, given the circle C: x2 + Y2 + 10x + 10Y = 0, point a (0, 6). (1) find the equation of circle n whose center is on the line y = x, passing through point a and tangent to circle C; (2) if the line m passing through point a intersects with circle C at P and Q, and the arc PQ is exactly 14 times the circumference of circle C, find the equation of line M

(1) Let n (a, a) (a > 0) be tangent to circle C. according to the meaning of the title, the tangent point is the origin o, and the radius is 2A. The equation of circle n is (x-a) 2 + (Y-A) 2 = 2A2. Substituting a (0, 6) into A2 + (6-A) 2 = 2A2, that is - 12a + 36 = 0, and the solution is a = 3, then the equation of circle n is (x-3) 2 + (Y-3) 2 = 18; (2) from the equation of circle C x2 + Y2 + 10x + 10 Y = 0, the deformation is: (x + 5) 2 + (y + 5) 2 = 50, the center of circle C (- 5, - 5), the radius is 52, from CD ⊥ P ′ Q ', we get CD = 5, D is the midpoint of P ′ Q', let x = 0 in the equation of circle C, we get y = 0 or y = 10, that is, P ′ Q ′ = 10, P ′ d = q ′ d = 5, ∵ y = x, the inclination angle is 45 °, that is, ∵ CP ′ d = 45 °, ∵ CDP ′ is isosceles right triangle, similarly, ∵ CDQ ′ is isosceles right triangle,