Factorization: (x-1) (X-2) (x-3) (x-4) - 48 using the method of Grade 8

Factorization: (x-1) (X-2) (x-3) (x-4) - 48 using the method of Grade 8

(x-1)(x-2)(x-3)(x-4)-48 =[(x-1)(x-4)][(x-2)(x-3)] =(x-5x+4)(x-5x+6)-48 =(x-5x)+10(x-5x)+24-48 =(x-5x)+10(x-5x)-24 =(x-5x+12)(x-5x-2）

How to factorize 8 (x + y) 3 + 1?

(x + y) 3 + 1 = [2 (x + y) 8 (x + y) 3 (x + y) 3 + 1 = [2 (x + y) 3 (x + y) 3 + 1 = [2 (x + y) 3 (x + y) 3 + 1 [2 (x + y) 3 + 1 = [2 (x + y) 3 (x + y) 3 + 1 [2 (x + y) 3 (x + y) 3 (x + y)] and [2 (x + y) is taken as a whole, and the formula a (x + X + y) is used as a whole, and then the formula a (x + y) is used to use the formula A and the formula a (a + b) (a (a (a (a) (a) (a) (A & \\\\\\\\\\\\\\+ 1) (4x & # 178; + 8

Using factorization method to solve the equation about X: a square x square + 2A square x + a square - b square = 0
Using factorization method to solve the equation about X: A & # 178; X & # 178; + 2A & # 178; X + A & # 178; - B & # 178; = 0

a²x²﹢2a²x﹢a²﹣b²=0
a²﹙x²﹢2x﹢1﹚﹣b²=0
a²﹙x﹢1﹚²﹣b²=0
﹙ ax﹢a﹢b﹚﹙ax﹢a﹣b﹚=0