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(2 a+3 b-c)² =[(2 a+3 b)-c]² 完全平方の数式を使う =(2 a+3 b)²-2 c(2 a+3 b)+c² =4 a²+12 a+9 b²-4 ac-6 bc+c²
-(2 a+3 b-1)^2
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