As shown in the figure, it is known that e is the midpoint of the edge BC of the square ABCD, and the point F is on the edge CD, and ∠ BAE = ∠ FAE

It is proved that if we make eg ⊥ AF through point E, the perpendicular foot is g, ∵ ∠ BAE = ∠ EAF, ∵ B = ∠ age = 90 ° and ∵ BAE = ∠ EAF, that is, AE is the angular bisector, EB ⊥ AB, eg ⊥ AG, ∵ be = eg, in RT △ Abe and RT △ age, be = egae = AE, ≌ RT △ Abe ≌ RT △ age (HL), ≌ Ag = ab

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1. As shown in the figure, in △ ABC, D is the point on AB, and ad = AC, AE ⊥ CD, the perpendicular foot is e, and F is the midpoint of CB
2. As shown in the figure, in the equilateral triangle ABC, the points D E are on AB AC respectively, and BD = AECD intersects be at the point O DF perpendicular be, and the point F is perpendicular to OD = 2of
3. In triangle ABC, we know that D is the midpoint of AB, e is the point on AC, and AE: EC = 2:1, be and CD intersect at O; (1) OC = OD （2）OB：EB=3;4
4. It is known that: as shown in the figure, in the equilateral triangle ABC, points D and E are on AB and AC respectively, and DB = AE, CD intersects be at points o, DF ⊥ be, and point F is perpendicular, 1) prove: ∠ Abe = ∠ BCD:2 ）Verification: od = 2of
5. It is known that, as shown in the figure, in the equilateral triangle ABC, points D and E are on AB and AC respectively, and BD is equal to AE, CD intersects be at point O, DF is perpendicular to be, and point F is To prove that OD is equal to 2of
6. As shown in the figure, the quadrilateral ABCD and aefg are both rhombic, in which point C is on AF, and points E and G are on BC and CD, respectively. If the angle bad = 135 degrees,
7. The quadrilateral ABCD and the quadrilateral aefg are both rhombic. The point E is on the ad side and the point G is on the extension line of the Ba side As shown in Figure 1, BD and CE are their diagonals. The extension line of Ge intersects BD at point Q and DC at point M. verify: GM ⊥ BD
8. Known: as shown in the figure, in the quadrilateral ABCD, ad ‖ BC, BD bisects AC vertically
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11. If f is any point on BC of square ABCD, AE bisects ∠ DAF intersecting CD and E, the proof is: AF = BF + De Can you get full marks in the senior high school entrance examination? You are only suitable for the analysis of filling in the blanks, but you will never get full marks for the answers. Now I'm sitting on the chair. What you did is wrong!
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