As shown in the figure, in the equilateral triangle ABC, the points D E are on AB AC respectively, and BD = AECD intersects be at the point O DF perpendicular be, and the point F is perpendicular to OD = 2of

As shown in the figure, in the equilateral triangle ABC, the points D E are on AB AC respectively, and BD = AECD intersects be at the point O DF perpendicular be, and the point F is perpendicular to OD = 2of

Because BD = AE triangle ABC is equilateral triangle, so AC = bcad = EC angle, BAC = angle BCE, so triangle BCE is congruent with triangle CAD, so angle BEC = angle ADC angle BEC = angle EAB + angle Abe angle ADC = angle DBE + angle DOB (angle DBE = angle ABE), so angle DOB = angle EAB = 60 ° DF is perpendicular to Bo, so triangle ODF is right angle three