It is known that, as shown in the figure, in the equilateral triangle ABC, points D and E are on AB and AC respectively, and BD is equal to AE, CD intersects be at point O, DF is perpendicular to be, and point F is To prove that OD is equal to 2of
1. In △ Abe and △ BEC, AE = BD, ∠ ABC = ∠ a, BC = ab.. Two △ congruent, that is ∠ Abe = ∠ bcd2. From the relationship between the complement angle and the inner angle of a triangle, ∠ EOC = ∠ OBC + ∠ OCB, we can see from the previous proof, ∠ Abe = ∠ BCD
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- 1. As shown in the figure, the quadrilateral ABCD and aefg are both rhombic, in which point C is on AF, and points E and G are on BC and CD, respectively. If the angle bad = 135 degrees,
- 2. The quadrilateral ABCD and the quadrilateral aefg are both rhombic. The point E is on the ad side and the point G is on the extension line of the Ba side As shown in Figure 1, BD and CE are their diagonals. The extension line of Ge intersects BD at point Q and DC at point M. verify: GM ⊥ BD
- 3. Known: as shown in the figure, in the quadrilateral ABCD, ad ‖ BC, BD bisects AC vertically
- 4. As shown in the figure, the quadrilateral ABCD, cdef and efgh are all square. (1) is △ ACF similar to △ GCA? Talk about your reasons; (2) find the degree of ∠ 1 + 2
- 5. As shown in the figure, the quadrilateral ABCD, cdef and efgh are all square. (1) is △ ACF similar to △ GCA? Talk about your reasons; (2) find the degree of ∠ 1 + 2
- 6. Quadrilateral ABCD, cdef, efgh are square, connect AC, AF, Ag, calculate the degree of angle AFB + angle AGB, thank you
- 7. As shown in the figure, the quadrilateral ABCD, cdef and efgh are all square. (1) is △ ACF similar to △ GCA? Talk about your reasons; (2) find the degree of ∠ 1 + 2
- 8. As shown in the figure, the quadrilateral ABCD, cdef and efgh are all square. (1) is △ ACF similar to △ GCA? Talk about your reasons; (2) find the degree of ∠ 1 + 2
- 9. In the geometry shown in the figure, the quadrilateral ABCD is a square, Ma ⊥ plane ABCD, PD ∥ Ma, e, G, f are the midpoint of MB, Pb, PC respectively, and ad = PD = 2mA. (I) verification: plane EFG ⊥ plane PDC; (II) calculation of the volume ratio of triangular pyramid p-mab and quadrangular pyramid p-abcd
- 10. As shown in the figure, ABCD is a square with side length of 2a, Pb ⊥ plane ABCD, Ma ∥ Pb, and Pb = 2mA = 2A, e is the midpoint of PD Verification: me ‖ plane ABCD Solution: cosine value of dihedral angle formed by plane PMD and plane ABCD Can you write me the specific process of the first question? I really don't understand. Please
- 11. It is known that: as shown in the figure, in the equilateral triangle ABC, points D and E are on AB and AC respectively, and DB = AE, CD intersects be at points o, DF ⊥ be, and point F is perpendicular, 1) prove: ∠ Abe = ∠ BCD:2 )Verification: od = 2of
- 12. In triangle ABC, we know that D is the midpoint of AB, e is the point on AC, and AE: EC = 2:1, be and CD intersect at O; (1) OC = OD (2)OB:EB=3;4
- 13. As shown in the figure, in the equilateral triangle ABC, the points D E are on AB AC respectively, and BD = AECD intersects be at the point O DF perpendicular be, and the point F is perpendicular to OD = 2of
- 14. As shown in the figure, in △ ABC, D is the point on AB, and ad = AC, AE ⊥ CD, the perpendicular foot is e, and F is the midpoint of CB
- 15. As shown in the figure, it is known that e is the midpoint of the edge BC of the square ABCD, and the point F is on the edge CD, and ∠ BAE = ∠ FAE
- 16. If f is any point on BC of square ABCD, AE bisects ∠ DAF intersecting CD and E, the proof is: AF = BF + De Can you get full marks in the senior high school entrance examination? You are only suitable for the analysis of filling in the blanks, but you will never get full marks for the answers. Now I'm sitting on the chair. What you did is wrong!
- 17. As shown in the figure, in square ABCD, ab = 3, points E and F are on BC and CD respectively, and ∠ BAE = 30 ° and ∠ DAF = 15 ° to calculate the area of △ AEF
- 18. In square ABCD, be = 3, EF = 5, DF = 4, how many degrees is the angle BAE + angle DCF?
- 19. As shown in the figure, ABCD is a square, point E is on BC, and DF ⊥ AE is on F. please determine a point G on AE to make △ ABG ≌ △ DAF, and explain the reason
- 20. As shown in the figure, the side length of square ABCD is 4, which is the midpoint of BC side, f is the point on DC side, and DF = 14dc, AE and BF intersect at G point. Find the area of △ ABG