It is known that, as shown in the figure, in the equilateral triangle ABC, points D and E are on AB and AC respectively, and BD is equal to AE, CD intersects be at point O, DF is perpendicular to be, and point F is To prove that OD is equal to 2of

It is known that, as shown in the figure, in the equilateral triangle ABC, points D and E are on AB and AC respectively, and BD is equal to AE, CD intersects be at point O, DF is perpendicular to be, and point F is To prove that OD is equal to 2of

1. In △ Abe and △ BEC, AE = BD, ∠ ABC = ∠ a, BC = ab.. Two △ congruent, that is ∠ Abe = ∠ bcd2. From the relationship between the complement angle and the inner angle of a triangle, ∠ EOC = ∠ OBC + ∠ OCB, we can see from the previous proof, ∠ Abe = ∠ BCD