Known: as shown in the figure, in the quadrilateral ABCD, ad ‖ BC, BD bisects AC vertically

AC intersects BD at O, and triangle ADO is similar to triangle BOC, so do = Bo,
A quadrilateral whose diagonals are perpendicular to each other and bisected is a diamond

RELATED INFORMATIONS

1. As shown in the figure, the quadrilateral ABCD, cdef and efgh are all square. (1) is △ ACF similar to △ GCA? Talk about your reasons; (2) find the degree of ∠ 1 + 2
2. As shown in the figure, the quadrilateral ABCD, cdef and efgh are all square. (1) is △ ACF similar to △ GCA? Talk about your reasons; (2) find the degree of ∠ 1 + 2
3. Quadrilateral ABCD, cdef, efgh are square, connect AC, AF, Ag, calculate the degree of angle AFB + angle AGB, thank you
4. As shown in the figure, the quadrilateral ABCD, cdef and efgh are all square. (1) is △ ACF similar to △ GCA? Talk about your reasons; (2) find the degree of ∠ 1 + 2
5. As shown in the figure, the quadrilateral ABCD, cdef and efgh are all square. (1) is △ ACF similar to △ GCA? Talk about your reasons; (2) find the degree of ∠ 1 + 2
6. In the geometry shown in the figure, the quadrilateral ABCD is a square, Ma ⊥ plane ABCD, PD ∥ Ma, e, G, f are the midpoint of MB, Pb, PC respectively, and ad = PD = 2mA. (I) verification: plane EFG ⊥ plane PDC; (II) calculation of the volume ratio of triangular pyramid p-mab and quadrangular pyramid p-abcd
7. As shown in the figure, ABCD is a square with side length of 2a, Pb ⊥ plane ABCD, Ma ∥ Pb, and Pb = 2mA = 2A, e is the midpoint of PD Verification: me ‖ plane ABCD Solution: cosine value of dihedral angle formed by plane PMD and plane ABCD Can you write me the specific process of the first question? I really don't understand. Please
8. As shown in the figure, the quadrilateral ABCD is a square, △ ADF is rotated to get △ Abe, ∠ 1 = ∠ 2, please judge: (1) the shape of △ AEG; (2) the relationship between Ag and BG + DF
9. If AF = 4, ab = 7, find: (1) point out the rotation center and rotation angle; (2) find the length of de; (3) what is the position relationship between be and DF? And explain the reason
10. The square ABCD and aefg common point a point Ge rotates aefg on ADAB, whether DF and BF are equal or not, it is incorrect to give a counter example Point G is on ad, point E is on AB, connect DF and BF, rotate square aefg around point a, whether DF and BF are still equal, incorrect, give a counterexample
11. The quadrilateral ABCD and the quadrilateral aefg are both rhombic. The point E is on the ad side and the point G is on the extension line of the Ba side As shown in Figure 1, BD and CE are their diagonals. The extension line of Ge intersects BD at point Q and DC at point M. verify: GM ⊥ BD
12. As shown in the figure, the quadrilateral ABCD and aefg are both rhombic, in which point C is on AF, and points E and G are on BC and CD, respectively. If the angle bad = 135 degrees,
13. It is known that, as shown in the figure, in the equilateral triangle ABC, points D and E are on AB and AC respectively, and BD is equal to AE, CD intersects be at point O, DF is perpendicular to be, and point F is To prove that OD is equal to 2of
14. It is known that: as shown in the figure, in the equilateral triangle ABC, points D and E are on AB and AC respectively, and DB = AE, CD intersects be at points o, DF ⊥ be, and point F is perpendicular, 1) prove: ∠ Abe = ∠ BCD:2 ）Verification: od = 2of
15. In triangle ABC, we know that D is the midpoint of AB, e is the point on AC, and AE: EC = 2:1, be and CD intersect at O; (1) OC = OD （2）OB：EB=3;4
16. As shown in the figure, in the equilateral triangle ABC, the points D E are on AB AC respectively, and BD = AECD intersects be at the point O DF perpendicular be, and the point F is perpendicular to OD = 2of
17. As shown in the figure, in △ ABC, D is the point on AB, and ad = AC, AE ⊥ CD, the perpendicular foot is e, and F is the midpoint of CB
18. As shown in the figure, it is known that e is the midpoint of the edge BC of the square ABCD, and the point F is on the edge CD, and ∠ BAE = ∠ FAE
19. If f is any point on BC of square ABCD, AE bisects ∠ DAF intersecting CD and E, the proof is: AF = BF + De Can you get full marks in the senior high school entrance examination? You are only suitable for the analysis of filling in the blanks, but you will never get full marks for the answers. Now I'm sitting on the chair. What you did is wrong!
20. As shown in the figure, in square ABCD, ab = 3, points E and F are on BC and CD respectively, and ∠ BAE = 30 ° and ∠ DAF = 15 ° to calculate the area of △ AEF