Quadrilateral ABCD, cdef, efgh are square, connect AC, AF, Ag, calculate the degree of angle AFB + angle AGB, thank you

Let the angle AFB be ∠ 2, and the angle AGB be ∠ 1. From the meaning of the question, we can know: AC = GCA square ABCD = > AC = root 2 * CD square cdef = > CD = CF so: AC = root 2 * CF and CF = FG (from the question), so CG = 2 * CF = root 2 * AC, then: AC / CF = CG / AC = root 2. At the same time: AC = GCA so: Triangle ACF is similar

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