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設角AFB為∠2角AGB為∠1由題意可知:∠ACF=∠GCA正方形ABCD=>AC=根號2*CD正方形CDEF=>CD=CF所以:AC=根號2*CF又知CF=FG(由題可知)所以CG=2*CF=根號2*AC則:AC/CF=CG/AC=根號2同時:∠ACF=∠GCA所以:三角形ACF相似…
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