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設正方形邊長為x,可知: ED=x/2,DF=x/4,根據畢氏定理得EF=根號5/4x, 同理可得, BE=根號5/2x,BF=5/4x, 此時BE平方+EF平方=BE平方 所以三角形BEF是直角三角形 所以BE垂直EF. (謹供參考)
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