Write down the inverse proposition of the following proposition, and judge the truth of the original proposition and the inverse proposition. (1) natural number must be rational number. (2) if | a | = | B | & _; then a = B (3) If a = B, then a ^ 3 = B ^ 3

Write down the inverse proposition of the following proposition, and judge the truth of the original proposition and the inverse proposition. (1) natural number must be rational number. (2) if | a | = | B | & _; then a = B (3) If a = B, then a ^ 3 = B ^ 3

(1) If a number is a rational number, it must be a natural number
(2) If a = B, then a | = | B |; the original proposition is wrong and the reverse proposition is correct
(3) If a ^ 3 = B ^ 3, then a = B; the original proposition is correct, so is the inverse proposition

In the following sentences, the correct number is () 1. Any rational number less than 1 is greater than its square. 2. The number without square is - 9. 3. If a > b, then A2 > B
In the following statements, the correct number is ()
① Any rational number less than 1 is greater than its square
② There is no square to get a number of - 9
③ If a > b, then A2 > B2
④ (M + 1) 2 is nonnegative
⑤ The cube of rational numbers greater than 0 and less than 1 must not be greater than the original number
⑥ The cube of a rational number greater than - 1 and less than 0 must be greater than the original number
(A) 1 (b) 2 (c) 3 (d) 4

0
If you learn plural, (2) Yes, the answer is 1

A 200 point mathematical problem, if a and B are rational numbers, and a + radical 2, B = (3-2 radical 2) square, then a =?, B =?

a+√2b=(3-2√2)²
a+√2b=17-12√2
Because a and B are rational numbers, so
a=17,√2b=-12√2
a=17,b=-12
Hope to help you ~ questions can be asked

Why does the absolute value disappear after deriving (LNU │) '= u' / u (implicit function)
Why?

When u > 0, (LN │ u │) '= (LNU)' = u '/ u
When U < 0, (LN │ u │) '= (LN (- U))' = - U '/ (- U) = u' / u

Simple calculation: 46.3 × 0.56 + 5.38 × 5.6-1 × 0.056 136.24 + 436.24 + 736.24 + 936.24

1. Original formula = 46.3 * 0.56 + 53.8 * 0.56-0.1 * 0.56
=（46.3+53.8-0.1）*0.56
=100*0.56
=56
2. The original formula = 100 + 400 + 700 + 900 + 36 * 4 + 0.24 * 4
=2100+144+0.96
=2244.96

There is a fraction, the numerator plus 2 equals 35, the numerator minus 2 equals 13

The original score is Ba, and the meaning of the question is: B + 2A = 35, 3A = 5B + 10, a = 5B + 2A = 35, 3A = 5B + 35, 3A = 5B + 10, a = 5B + 103, B − 2A = 13, and a = 3b-6, so you can get 5B + 103 = 3b − 6, and then you can get 5B + 103 = 3b-6, and then you can get 5B + 103 = 3b-6, and then you can get 5B + 103 = 5B + 103 = 3b − -6, & nbsp & nbsp & nbsp; & & nbsp; & & nbsp; & nbsp; & & nbsp; & & nbsp; & & nbsp; & & nbsp; & & nbsp; & & nbsp; & nbsp; & & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & nbsp; & & nbsp; & nbsp; & nbsp; B = 7, a = 3b-6, = 3 × 7-6, = 21-6, = 15, so the original score is 715

Given that G (x) = - x * x-3, f (x) is a quadratic function. When x is in the closed interval of - 1 to 2, the minimum value of F (x) is 1, and f (x) + G (x) is an odd function,
Finding the expression of function f (x)

G (x) is a quadratic function, f (x) is also a quadratic function, then f (x) + G (x) must be a quadratic function, that is, f (x) + G (x) = ax ^ 2 + BX + C, where a and B may be equal to zero. F (x) + G (x) is an odd function, then f (0) = 0, so C = 0. At the same time, f (1) = - f (- 1), so a + B = - A + B, so a = 0. Then f (x) + G (x) = BX, f (x) = x ^ 2 + BX + 3
Let's consider the minimum value of F (x). The vertex of quadratic function is obtained at x = - B / 2. Note that we need to discuss the relationship between [- 1,2] interval and vertex to calculate the minimum value of quadratic function on the interval
In the first case, - B / 22, f (x) increases monotonically at [- 1,2], and the minimum value 1 is obtained at - 1, so 1 = f (- 1) = 1-B + 3, B = 3 meets the requirements
In the second case, - B / 2 > 2, B-4 does not meet the requirements
In the third case, - 1

What can be calculated simply is 63720 ／ 59 ／ 15 + 102 {0.375 + 10.8} - {4 / 5-8 / 5}?

63720÷59÷15＋102
=1080÷15+102
=72+102
=174
{0.375 + 10.8} - {4 / 5-8 / 5}
=0.375+10.5-（-0.8）
=0.375+10.5+0.8
=11.675

LIM (when x tends to 0) [(e ^ x + e ^ 2x + e ^ 3x +...) What is the limit of e ^ NX) / N] ^ (1 / x), where n is a finite value
LIM (when x tends to 0) [(e ^ x + e ^ 2x + e ^ 3x +...) Where n is a finite value

We can use the equivalent infinitesimal ln (1 + x) = x and the law of lobita,
Its limit is e ^ (n + 1) / 2
Original formula = exp {Lim {1 / X * ln [1 + (e ^ x + e ^ 2x +... + e ^ nx-n) / N]}}
x->0
=Exp [LIM (e ^ x + e ^ 2x +... + e ^ nx-n) / NX] - type 0 / 0
x->0
=exp[lim(e^x+2e^2x+...+ne^nx)/n]
x->0
=Exp (n + 1 / 2) --- e ^ x = 1 when X - > 0
That is, its limit is e ^ [(n + 1) / 2]

Read the following materials for the equation of one degree with one variable. Materials: try to discuss the solution of the equation AX = B. when a ≠ 0, the equation has

I've answered three times
Compared with material solution
A (2x-1) = 3x-2 is transformed into the form AX = B, i.e
2ax-a=3x-2
（2a-3）x=a-2
So when 2a-3 = 0, A-2 ≠ 0, the equation has no solution
That is 2a-3 = 0, the solution is a = 1.5