How to divide 800 by 32 in a simple way

How to divide 800 by 32 in a simple way

=800÷（8×4）
=800÷8÷4
=100÷4
=25

125 × (8 × 4) = 125 × 8 + 125 × 4 = 1000 + 500 = 1500, right?

Exactly

There are seven natural numbers, the remainder of which divided by 7 is different, so what is the remainder of their sum divided by 7?

7 continuous, then there is a remainder of 0, which is the smallest group {1,2,3,4,5,6,7}, and the remainder of 0

The sum of 2000 consecutive natural numbers from 1 to 2000 divided by 17 gives the remainder______ ．

（1+2+3+4+5+… +1999+2000）÷17，=（1+2000）×（2000÷2）÷17，=2001000÷17，=117705… 15. So the answer is: 15

There is a natural number divided by 33 and more than 12, divided by 43 and more than 7______ ．

Let the natural number be x, then x = 33n + 12 = 43M + 7, 33 (n-m) + 5 = 10m, M = 33 (n-m) 10 + 12. Because m is a natural number, it is the minimum when N-M = 5, M = 33 × 510 + 12 = 17, X = 43 × 17 + 7 = 738

There is a natural number divided by 33 and more than 12, divided by 43 and more than 7______ ．

Let the natural number be x, then x = 33n + 12 = 43M + 7, 33 (n-m) + 5 = 10m, M = 33 (n-m) 10 + 12. Because m is a natural number, it is the minimum when N-M = 5, M = 33 × 510 + 12 = 17, X = 43 × 17 + 7 = 738

Write the natural number from 1, stop when writing to 2008, get a multi digit number: 123456789 2008 please explain: what is the remainder of the number divided by 3? Why?

（1+2+3+… +2008）=（1+2008）×2008÷2=2017036．（2+1+7+3+6）÷3，=19÷3，=6… 1. The original number 123 can be deduced 2008 is divided by 3, the remainder is 1

Write the natural number from 1, stop when writing to 2008, get a multi digit number: 123456789 2008 please explain: what is the remainder of the number divided by 3? Why?

（1+2+3+… +2008）=（1+2008）×2008÷2=2017036．（2+1+7+3+6）÷3，=19÷3，=6… 1. The original number 123 can be deduced 2008 is divided by 3, the remainder is 1

If the remainder of 2008 divided by the natural number m is 10, how many such m are there

The remainder is 10, so m is a divisor of 2008-10 = 1998, and m ＞ 10
Decompose 1998 into
2 * 3 * 3 * 3 * 37, its divisors are (1 + 1) * (3 + 1) * (1 + 1) = 16
There are five divisors less than 10: 1, 2, 3, 6 and 9
16-5=11

A number greater than 10, divided by 5 over 3, divided by 7 over 1, divided by 9 over 3, asks the minimum natural number satisfying the condition
Ask about the solution and the answer
Excuse me, if it is more than 9 8? Method and answer. Thank you

5. The least common multiple of 7 and 9 is 5 * 7 * 9 = 315
7*9+5*9*5+5*7*6=63+225+210=498>315
498-315=183 (