Who is the biggest between 2000 * 2000 + 2004 * 2004 and 2001 * 2001 + 2003 * 2003

Let x = 2000
Change to x ^ 2 + (x + 4) ^ 2 and (x + 1) ^ 2 + (x + 3) ^ 2, then subtract the two expressions and use them as the difference comparison method
it's fine too
2000*2000+2004*2004 -( 2001*2001+2003*2003)
=(2000*2000- 2001*2001)+(2004*2004 -2003*2003)
=(2000-2001) * (2000 + 2001) + (2004-2003) * (2004 + 2003) square difference formula
=-4001 + 4007 = 6 > 0, so the former is greater than the latter

One 2 ^ 2003 times one 0.5 ^ 2004 =?

164357

A ^ 2 + A + 1 = 0, find the value of a ^ 2004 + A ^ 2003 +.. + A + 5

A ^ 2004 + A ^ 2003 +.. + A + 5 = a ^ 2002 (a ^ 2 + A + 1) + A ^ 1999 (a ^ 2 + A + 1) +... A (a ^ 2 + A + 1) + 5 = 5 note: there are 2004 from a ^ 1 to a ^ 2004, just 668 groups, 3 in each group, and the value of each group is 0

（-2）^2004(-0.5)^2003+(-97/14)7
It's the whole process

(-2）^2004*(-0.5)^2003+(-97/14)*7
Change (- 0.5) ^ 2003 to - 2 ^ (- 2003)] to
2^2004*[-2^(-2003)]=-2^(2004-2003)=-2
(-97/14)*7=-97/2=-48.5
（-2）^2004*(-0.5)^2003+(-97/14)*7=-2-48.5=-50.5
Upstairs funny, - 1 / 2-97 / 2 = 49, it's positive

Given a ^ 2 + A + 1 = 0, find a ^ 2004 + A ^ 2003 + A ^ 2002 +. + A + 5

Group of three
The original formula = a ^ 2002 (A & # 178; + A + 1) + A ^ 2019 (A & # 178; + A + 1) + +a(a²+a+1)+5
=0+0+…… +0+5
=5

The simple calculation is: 780 △ 205-145 and (180-140) × 7-123
Urgent!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

780÷（205—145）=780÷80=9.75
（180—140）×7—123 =40x7-123=280-123=157

Simple algorithm of 123 × 18-123 × 3 + 85 × 123

123×(18-3+85)=123×100

How to calculate 123 △ 25

The divisor and divisor are multiplied by a nonzero number at the same time, and the quotient remains unchanged
123÷25
＝（123×4）÷（25×4）
＝ 492÷100
＝ 4.92

123+111=

123 + 111 = 234

123=123-111-14=654

yes 123=123

Who is the biggest between 2000 * 2000 + 2004 * 2004 and 2001 * 2001 + 2003 * 2003